Question 1
140 km
145 km
150 km
155 km
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First train start in 10 am and 2nd train start train 10:30 So the 1st train cover 30 km distance in 10:30. Now, both train time are equal Let the train distance = x time 1= time 2 x-30/60=x/75 So x=150 km
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((d/60)-(d/75)=1/2 d=150
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Question 2
47
40
35
45
28 children can do a piece of work in 50 days ⇒ 50 days = 28 children The number of days is inversely proportional to the number of children. ⇒ The more days we have, the fewer children we need Find number of children needed to complete the work in 1 day: 50 days = 28 children 1 day = 28 x 50 = 1400 children Find number of children needed to complete the work in 30 day: 1 day = 1400 children 30 days = 1400 ÷ 30 = 46.67 ≈ 47 complete days Answer: 30 children will need 47 days to complete the work.
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Question 3
6.12 kmph
6.42 kmph
6.22 kmph
6.32 kmph
A\'s Speed:B\'s Speed=rootof(b):rootof(a) =>8:x=rootof(10/3):rootof(16/3) On solving we get, => x=2*rootof(10) => x=2*3.16 => x=6.32 kmph.
Question 4
24 days
21 days
18 days
15 days
15 days Work = 28 * 6 * 15 --- (1) Work = 21 * 8 * x -- - (2) Equating (1) and (2) 28 * 6 * 15 = 21 * 8 * x X= 15
Question 5
50m
150m
100m
200m
200 m Speed = distance/time; Distance= speed * time = (60-45) * 48 * ( 5/18) ( relative speed in same direction is s1-s2 and kmph to m/sec 5/18) = 200m
Question 6
44.4 kmph
57.6 kmph
33.3 kmph
22.2 kmph
Length of the Train = 240 m. Time taken by it to cross the Pole = 15 seconds. ∵ Speed = Distance or length of the train/Time ∴ Speed = 240/15 ⇒ Speed of the train = 16 m/s = 16×3.6 km/h = 57.6 km/h The speed of the train is 57.6 km/h.
Question 7
120m
175m
Let length of platform = P m we know, distance = speed × time here, time = 1.5 × 60 sec = 90 sec speed = 54 × 5/18 = 15 m/s distance = (1200 + P) m 1200 + P = 15 × 90 1200 + P = 1350 P = 150 m hence, Length of platform = 150 m
Question 8
30 sec
42 sec
40 sec
45 sec
Let the speeds of the trains be A and B and their length be L A = L/4 B = L/5 now when they move in same direction to cross one train, the other train has to cover 2L distance now relative velocity = L/4 - L/5 = L/20 therefore time taken = 2L/L/20 = 40 sec
Question 9
Between 100 and 700
Less than 100
More than 900
More than 700
Question 10
4 a.m.
4 p.m.
5 a.m.
5 p.m.
With 60 kmph in 3 hours train ‘A’ covers 180 kms. Train B speed is 12kmph more than train ‘A’. Because train B started 3 hours later so it has to cover 180 extra with extra 12kmph speed. Time taken is = 180/12 = 15 hours So 15 hours from 2p.m is 5a.m on the next day
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