Wipro Elite National Talent Hunt 2020 | Wipro Elite

Wipro Elite National Talent Hunt 2020

Wipro Elite National Talent Hunt 2020 also known as Wipro Elite 2020 National Level Talent Hunt, Registration for 2020 PassOut Batch is explained on this page, make sure that you follow all, each and every step mentioned on this page. As last time for 2019 Batch 10% students who filled the form incorrectly didn’t get their hall tickets. So make sure that you follow each step mentioned on this age. 

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Wipro Elite National Level Talent Hunt 2019
Registration Starts 12th September, 2019
Last Day To Apply 23rd September, 2019
Hall Ticket Issue 11th October, 2019
Online Test 18, 19 & 20th October, 2019
Interview Starts on 31st October, 2019

Wipro Elite National Level Talent Hunt 2019-2020 | Job Role Offered

Wipro will be Selecting Engineering Students all over India for their Elite Natinal Level Talent Hunt 2019-20  Recruitment to take the best students who match their company criteria. The job roles offered by Wipro after the Elite National Level Talent Hunt  Recruitment Process for freshers are:

Job Role and Service AgreementCTC
Project Engineer INR 3.50 lacs per annum
Service AgreementApplicable for 15 months post joining @ INR 75,000 on pro rata basis

 

National Level Talent Hunt - Eligibility Criteria | Wipro Elite

Education Qualification

  • College Graduation CGPA 60% or above
  • 10th Class : 60% or Above
  • 12th Class: 60% or above
  • Maximum of 3 years of education gap
  • No Arrear or Backlog at the time of Selection Process
  • If attended any Wipro Interview Process in the last 6 months are not eligible for the Wipro Elite National Level Talent Hunt 2019

Year of Passing

  • 2020 as Year of Passing

Qualification & Branch Eligible

  • B.E./B.Tech/5 years Integrated – M.Tech
  • All Branches Eligible


Wipro Elite National Level Talent Hunt 2019-20 - Hiring Process

All the eligbile Candidates have to go through 3 Rounds of Selection Process

  1. Online Assessment
  2. Technical Interview Round
  3. Hr Interview Round

Below we have explained all the rounds in detail : –

Round 1: Online Written Test

Wipro Elite National Level Talent Hunt 2019-20 will conduct a written/online assessment test to evaluate the basic aptitude knowledge of a candidate. 

Online Assessment  is of 140 minutes comprising of 3 sections:

  • Aptitude Test – Logical Ability , Quantitative Ability , English (verbal) Ability

    Duration: 60 mins

  • Written Communication Test – Essay writing.
    Duration: 20 mins
  • Online Programming Test – Two programs for coding.
    Duration: 60 mins
    Candidate can chose any one of programming language for coding test out of  Java, C, C++ or Python

Round 2: Techincal Interview Round

Post Clearing the Online Written Test, the selected candidates will be called over for the Technical Interview Round for Elite National Level Talent Hunt 2019

  • Important Points to keep in mind:
    • Learn about the Final Year Project – In-Depth
    • Learn One Coding Languague
    • Learn about the latest technologies used in companies

Round 3: HR Interview Round

Students who will clear the Technical Interview Round will be selected for the final round of selection process i.e. Hr Interview Round

  • Important Points to keep in mind:
    • Brush-Up your Vocabulary & English Speaking Skills
    • Talk about being a Team Player
    • Talk about Environmental Protection & Social Issues

Wipro NLTH Sample Questions:-

Question : Which one of the below-given options would be a meaning full order of the following words.

1. Grasshopper  2. Eagle  3. Frog 4. Grass  5. Snake

a) 4, 1, 3, 5, 2

b) 4, 1, 5, 3, 2

c) 1, 4, 2, 3, 5

d) 2, 5, 3, 1, 4

Answer :    a)

Explanation :

Grass -> Grasshopper -> Frog -> Snake -> Eagle

Question : If tour one includes E and tour two includes A, which of the following MUST be included in tour two?

a) F

b) B

c) H

d) None of the above

Answer: d)

Explanation:

• Tour one must include E and tour 2 must include A, as per the given question.

• By following the condition 4, G cannot be placed in tour 2 with A. So, G goes into tour 1.

• According to condition 3, F should be included in tour 1 along with E.

• And considering the condition one, B goes into tour 1.

• Applying condition 2 is only possible in tour 2 here in this case, because two slots are only available in tour 2.

So the conclusion arrived will be:

Tour 1: E F H B G

Tour 2: A C D

Question : By what number should be 86700 divided to make it a perfect square?

a) 2

b) 5

c) 4

d) 3

Answer:  d)

Explanation:

 First Prime Factorize 86700, that Gives;

86700 = 2×2×5×5×3×17×17

As factor of 3 is not in Pair.

86700 should be divided by 3 to get a Perfect Square

i.e.- 86700/3  = 28900

Question : Select the word or phrase which best expresses the meaning of the given word: Germinate

a) Decay

b) Breed

c) Produce

d) Sprout

Answer: c)

Explanation:

Decay : rot or decompose through the action of
bacteria and fungi.
Produce : make or manufacture from components or raw
materials.
Sprout : put out shoots.
Breed : mate and then produce offspring.
Germinate : begin to grow and put out shoots after a period
of dormancy.

Question : Choose opposite word for-

The whole town was in Amity after the disaster stuck

a) Affection

b) Mercy

c) Malevolence

d) Lenity

Answer: c)

Explanation: 

Malevolence means enmity or hate

Question : A card is drawn from a well-shuffled pack of cards. The probability of getting a queen of club or king of the heart is?

a) 1/52

b)1/26

c) 1/13

d) None of the Above

Answer: b)

Explanation:

Total ways = 52
There is one queen of club and one king of heart favorable ways = 1 + 1 = 2.
∴ Required probability = 2/52 = 1/26

Question : Find the greatest number which on dividing 1661 and 2045, leaves a remainder of 10 and 13 respectively?

a) 125

b) 129

c) 127

d) 131

Answer:c)

Explanation:

In this type of question, its obvious we need to calculate the HCF, trick is
HCF of (1661 – 10) and (2045 -13)
= HCF (1651, 2032) = 127

Question : A dealer buys dry fruits at the rate of ` 100, ` 80 and ` 60 per kg. He bought them in the ratio 12 : 15 : 20 by weight. He in total gets 20% profit by selling the first two and at last he finds he has no gain or no loss in selling the whole quantity which he had. What was the percentage loss he suffered for the third quantity?

a) 30%

 b) 40%        

c) 20

d) 50%

Answer: b) 40

Explanation: Total quantity rate =
(12 * 100 + 15 * 80 + 20 * 60) = 3600
For first 2 quantity, (12 * 100) + (15 * 80) = 2400
But he gets 20% profit = 2400 * 1.2 = 2880
So the third quantity = 3600 – 2880 = 720
Actual third quantity rate = 20 * 60 = 1200
Loss suffered = (1200 – 720) / 1200
= 480/1200 = 40 %

Question : The profit obtained by selling an article for Rs 480 is twice the loss obtained by selling for Rs 300. What is the cost price of the article?

a) 350       

b) 330       

c) 340        

d) 360

Answer:   d) 360

Explanation:

Here profit is the twice the loss
Profit = 2 Loss
SP –CP = 2 (CP – SP)
480 –CP = 2(CP – 300)
3 CP = 1080
CP= 360

Wipro Elite National Level Talent Hunt 2019-20| FAQs

Question : What is the eligibility criteria for Wipro Elite National Level Talent Hunt ?

 Answer: For the information on the eligibility criteria for Wipro elite National Level Talent Hunt please do visit our eligibility criteria page for the same.

Question : Can I get the information of selection procedure for Wipro Elite National Level Talent Hunt 2019-20 ?

Answer: There are basically 3 rounds for the eligible students. These three rounds are as follows :
                   1 Online Assesment
                   2 Technical interview Round
                   3 HR Interview Round

Question : What will be the pay structure for Selected Students through Wipro Elite National Level Talent Hunt 2019-20  ?

Answer: As per the policy of wipro the students who pass through the interview procedure of Wipro Elite National Level Talent Hunt are offered a package of 3.5 lakhs INR
 
 
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