Hexaware HCF and LCM Quiz 1

(6*12*18)/24

The next number will be = 54

The LCM of 5, 10, 15, 20 and 25 is 300

Therefore the street lamps start at an interval of 5 minutes

In 40 minutes they will start together in 40/5 = 8

The largest number = (60-12), (90-60), and (90-12)
= H.C.F = 48, 30, and 78
48 factors are 2 x 2 x 2 x 3
30 factors are 2 x 3 x 5
78 factors are 2 x 3 x 13
H.C.F is 2 x 3=6

2|55, 66, 88

2|55, 33, 44

2|55, 33, 22

3|55, 33, 11

5|55, 11, 11

11|11, 1, 1

|1, 1, 1

= L.C.M = 2*2*2*3*5*11 = 1320

The L.C.M of 14, 18 and 16 will be

= 1008 +1 = 1009

We have to find the hcf of(294-4,396-6)
i.e hcf(290,390)
since 294 and 396 will be completely divisible by that number
so the answer will be 10
(when 294/10 remainder is 4
when 396/10 remainder is 6)

Let the given numbers be 2y and 3y

L.C.M = 60

L.C.M = 2y x 3y=6y

According to question:

6Y = 60

=>Y = 10

So the numbers will be 2*10 = 20

And 3*10 = 30

And their sum will be 20+30 = 50

20* 10 = 200

20*12 = 240

So the larger number will be 240

2|15, 30, 45

3|15, 15, 45

3|5, 5, 15

5|5, 5, 5

_____________

1, 1, 1

L.C.M = 2*3*3*5 = 90

22 = 2*11

33 = 3*11

So the HCF will be 11