WeCP Coding Deductive Logic Quiz 1

Ans.(B)

Sol. Putting A = 1, B = 2, C = 3, ….. X = 24, Y = 25, Z = 26, we have:

SNAKE → S/N/A/K/E → 19/14/1/11/5 → 19141115

CHIMPANZEE→ C/H/I/M/P/A/N/Z/E/E → 3/8/9/13/16/1/14/26/5/5 → 38913161142655

Ans.(b)

The code for TRAIN is $%÷#×.

Ans.(c)

Sol. Aeroplane is fly in the sky. But aeroplane is called yellow. So, yellow is the correct answer.

Ans.(d)

Sol.

‘123’ -> ‘bright little boy’   …..(i)

‘145’ -> ‘tall big boy’       …..(ii)

‘637’ -> ‘beautiful little flower’    …..(iii)

From (i) & (ii) we get ‘1’ means ‘boy’.

From (i) & (iii) we get ‘3’ means ‘little’.

Thus, in (i) statement ‘2’ means ‘bright’.

Ans. - (A)

Sol. Let A = 1, B = 2, C = 3, ……, X = 24, Y = 25, Z = 26

Then, M = 13 = 1 + 3 = 4;

O = 15 = 1 + 5 = 6;

B = 2; I = 9;

L = 12 = 1 + 2 = 3

T = 20 = 2 + 0 = 2;

Y = 25 = 2 + 5 = 7

So, MOBILITY = 46293927.

Similarly, X = 24 = 2 + 4 = 6; N = 14 = 1 + 4 = 5.

So, EXAMINATION = 56149512965

Ans. - (C)

Sol. Clearly, we have:

Ans.(d)

Sol. The code for QKTBFM is 452863.

Answer - Option B

Given P = 16 which means P is the 16th letter in alphabet series

PAINT = 16 + 1 + 9 + 14 + 20 = 60

Similarly,

PLASTER = 16 + 12 + 1 + 19 + 20 + 5+ 18 = 91

Ans. - (b)

Sol. Student use sharpener to sharp pencil. But sharpener is pencil. So, pencil used by student to sharp pencil.

Ans. - (c)

Sol.

‘ski rps tri’ -> ‘nice Sunday morning’  ……(i)

‘teh sti rps’ -> ‘every Tuesday morning’ …..(ii)

‘ski ptr qlm’ -> ‘nice market place’      ……(iii)

From (i) & (ii) we get ‘rps’ stands for ‘morning’.

From (i) & (iii) we get ‘ski’ stands for ‘nice’.

Thus, in (i) statement, ‘tri’ stands for ‘Sunday’.