Quiz-1

At present

Age of Umesh = x

Age of Reena is Y age of Mahesh is m

after 6 years

X+6=4(y+6)

X+6=4y+24

But it is given that age of Mahesh is equal to 7 times age of Reena

So

7y+6=4y+24

3y+6=24

3y=18

Y=6

Age of Mahesh is equal to 7 times the age of Reena

X=7*6

=42

Lets Ramesh's present age be x years. Then,
Ramesh's age after 16 years = (x + 16) years
Ramesh's age 4 years back = (x – 4) years
Therefore, x + 16 = 5(x – 4)
x+16 = 5x – 20
4x = 36
x = 9
Hence, Ramesh's present age = 9 years.

Total Age of 10 students and Teacher = 11 x 15 = 165

Total age of first 7 students = 7 x 15 = 105

Total age of 3 students = 3 x 11 = 33

Thus total age of students = 33 + 105 = 138

Age of Teacher = 165 - 138 = 27

 

Since its 13 years ago

Nina's 13 year ago age = Present age - 13 = 37 - 13 = 24

Aman 13 year ago age = Present age - 13 = 59 - 13 = 46

Ratio = 24/46 = 12:23

Step-by-step explanation:

Average age of a family of 4 members was 19 years, 4 years back.

Let the ages of 4 members be a,b,c,d 4 years ago

19 =sum of all ages/4

19 = a+b+c+d/4

19 *4 = a+b+c+d

76 = a+b+c+d

So, the sum of ages of 4 members 4 years ago is 76

Now after four years their ages will be increase by 4

So, the sum of ages of 4 members after 4 years = a+4+b+4+c+4+d+4

=a+b+c+d+16

= 76+16

= 92

Let the present age of baby be x

Sum of ages of 4 members and baby = 92+x

Now total members = 4+1=5

the average age of the family same even today.

So, 19 = (92+x)/5

19 * 5 =92+x

95 =92+x

x=3

Total age of all the 6 family members=36*4=144

6 years ago the youngest member was not there and the other members were 6 years younger than now.

so the total age of a family of 3 members will be 144-(6*4)=120.

Therefore the average age of 3 members will be 120/3 = 40 years

Let the present ages of Amit and Dhiraj be 5x years and 4x years respectively. Then,
5x + 6 = 26
5x = 20
x = 4
Dhiraj’s age = 4x = 16 years

Let the ages of husband and wife at the time of their 20th wedding anniversary be X years and Y years respectively and X > Y.
Their combined age = (X + Y) years.
The ages of both husband and wife at the time of wedding will be (X – 20) years and (Y – 20) years respectively.
Their combined age = (X – 20) + (Y – 20)
= (X + Y – 40) Years
By first information, we have
(X + Y) = 2( X + Y – 40)
X + Y = 2X + 2Y - 80
Therefore, X + Y = 80-------A
and by second information, we have
X – Y =3 ----------------------B
Solving A and B, we get X = 41.5 years
Therefore, the age of husband at the time of their 20th wedding anniversary X = 41.5 years
Age at the time of marriage = 41.5 years – 20 years = 21.5 years.

Let Neha's present age be 'x' years.
Her age 12 years ago = (x – 12) years
Therefore, her mother's age 12 years ago = 4(x – 12)
Her mother's present age = 4x – 48 + 12 = 4x – 36
Neha's age after 12 years = x + 12
Her mother's age after 12 years = 4x – 36 + 12 = 4x – 24
4x – 24 = 2(x + 12)
4x – 2x = 24 + 24
x = 24
Therefore, Neha's present age = 24
Her mother's present age = 4x – 36 = 4(24) – 36 = 60 years