Leap Year Program in Python

August 11, 2023

Leap-year-or-not-using-python

Check if a Year is a Leap Year or Not in Python

Given an integer input year, the objective of the code is to Check if a Year is a Leap Year or Not in Python Language. To do so  we’ll check if the year input satisfies either of the two conditions of leap year.

Example
Input : 2020
Output : It's a Leap Year.

Check Whether a Year is a Leap Year or Not in Python

Given an integer input as the year, the objective is to Check if a Year is a Leap Year or Not in Python Language. To do so we’ll check each condition mentioned below in the blue box. It either of the conditions is satisfied, the year is a leap year. It’s not otherwise. Here are some methods to check whether or not it’s a leap year

  • Method 1: Using if-else statements 1
  • Method 2: Using if-else statements 2
  • Method 3 : Using Ternary Operator
  • Method 4 : Using Calendar Mode
  • Method 5 : Using Lamda Function

We’ll discuss all the above mentioned methods in detail in the upcoming sections. Before going for the approach read out the blue box below for better understanding of the concept.

Greatest of two numbers

Greatest of the Three numbers

Prime number

Prime number within a given range

Sum of digits of a number

Method 1: Using if-else Statements 1

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. To learn more about control statements in python, check out if-else control statements in Python.

Working

For a User Input year we do

  1. Check if the year variable is divisible by 400.
  2. Check if the year variable is divisible only by 4 and not 100.
  3. If the above mentioned conditions are satisfied, prints “Leap Year”, print “Not a Leap Year” otherwise.

Let’s implement the above logic in Python Language.

Python Code

Run
year = 2000

if (year%400 == 0) or (year%4==0 and year%100!=0):
    print("Leap Year")
else:
    print("Not a Leap Year")

Output

Leap Year

Method 2: Using if-else Statements 2

In this method we’ll use the if-else statements to check whether or not the input integer satisfies either of the conditions. This method is a modified and simpler version of the previous method.

Working

For a User Input year we do

  1. The input is stored in an int type variable say year.
  2. year is checked for being a leap year or not with the following condition if( ((year % 4 == 0)&&(year % 100 != 0)) || (year % 400==0) )
  3. If the above condition is true then input is a leap year otherwise input is not a leap year.

Let’s implement the above logic in Python Language.

Python Code

Run 
year = 2000
if( ((year % 4 == 0) and (year % 100 != 0)) or (year % 400==0) ):
    print("Leap Year")
else:
    print("Not leap Year")

Output:

Leap Year

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Method 3: Using Ternary Operator

In this method we’ll use ternary operator in Python

Python Code

Run 
def check_leap(year): 
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) 

year = int(input("Enter a year: ")) 

print(f"{year} is leap year" if check_leap(year) else f"{year} is not leap year")

Method 4: Using Calendar Module

In this method we’ll use calendar mode in python

Python Code

Run

import calendar

year = int(input("Enter a year: "))

if calendar.isleap(year):
    print(year, " is a leap year")
else:
    print(year, "is not a leap year.")

Python Code

Method 5: Using Lamda Function

In this method we’ll use lamda function in python

Run 
is_leap_year = lambda year: (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

year = int(input("Enter a year: "))

if is_leap_year(year):
    print(year, " is a leap year")
else:
    print(year, "is not a leap year.")

38 comments on “Leap Year Program in Python”


  • MAITHREYI

    year=int(input())
    if (year%400==0):
    print(“Leap Year”)
    elif(year%4==0 and year%100!=0):
    print(“Leap Year”)
    else:
    print(“Not Leap Year”)


  • Ganesh

    # Write your code
    year = int(input(‘enter year:’))
    if year% 4 == 0:
    print(year, ‘is a leap year’)
    else:
    print(year, ‘is not a leap year’)


  • Abhishek

    year=int(input())
    if year%4==0:
    if year%100==0:
    if year%400==0:
    print(“yes it is leap year”)
    else:
    print(“NO it is not leap year”)
    else:
    print(“yes it is leap year”)
    else:
    print(“NO it is not leap year”)


  • Bibhudutta

    a=int(input())

    if(a%4==0 and a%100!=0) or (a%400==0 and a%100==0):
    print(a,’ is a leap year’)
    else:
    print(“Not a leap year”)


  • Amol

    #Please check this one hacker rank proven
    year=int(input(“Enter the year:”))

    if (year%4==0) or (year%100==0 and year%400==0):
    print(“Yes {} is leap year”.format(year))
    else:
    print(“No,{} is not leap year”.format(year))


  • Abhishek

    year = int(input(“ENTER THE YEAR:— “))
    if year % 4 == 0:
    if year % 100 == 0:
    if year % 400 == 0:
    print(” {0} YEAR IS A LEAP YEAR “.format(year))
    else:
    print(“THIS IS NOT A LEAP YEAR”)
    else:
    print(“THIS IS A LEAP YEAR”)
    else:
    print(“THIS IS NOT A LEAP YEAR”)


  • Poonam

    n=int(input(“Enter the year:”))
    if n%4==0 and n%100==0 and n%400==0:
    print(“Leap year”)
    else:
    print(“Not leap year”)


  • ankush

    x = int(input())
    if x % 100 == 0:
    if x % 400 == 0:
    print(“{} is leap year”.format(x))
    else:
    print(“{} is not leap year”.format(x))
    if x % 100 != 0:
    if x % 4 == 0:
    print(“{} is leap year”.format(x))
    else:
    print(“{} is not leap year”.format(x))


  • Sonal

    year=int(input(“Enter the year “))
    if(year%4==0 and year%100!=0) or (year%400==0):
    print(year,”is a leap year”)
    else:
    print(year,”is not a leap year”)

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