Program to Check Whether a Year is a Leap Year or Not in C++
Program to Check Whether a Year is a Leap Year or Not in C++
Given an integer input for a year, the objective is to write a Program to Check Whether a Year is a Leap Year or Not in C++ Language.
Example Input : 2020 Output : 2020 is a Leap Year
Program to Check if the Year is a Leap Year or Not in C++ Language
Here we will discuss how to check whether a year is a leap year or not using the C++ programming language. In a year there are 365 days, but once every fourth year there are 366 days that year is called a leap year. The objective is to write a Program to Check if the Year is a Leap Year or Not in C++ Language. Here are few methods to check for leap years
- Method 1: Using if-else Statements 1
- Method 2: Using if-else Statements 2
- Method 3: Using Ternary Operator
- Method 4: Complicated if-else statements (Not recommended)
We’ll discuss the above mentioned methods in detail in the sections below. Before we dive in, check the conditions for Leap Year mentioned below.
1. If a year is divisible by 400, it's a leap year.
2. If a year is divisible by 4 but not by 100 then its leap year
Method 1: Using if-else Statements 1
In this method we’ll use the if-else statements to check for the above mentioned conditions one by one.
Working
For user input year check
- If year % 400 == 0
- Print Leap Year
- Else If year % 4 == 0 && year % 100 != 0
- Print Leap Year
- Else, year will be not leap
Let’s implement the above logic in C++ Language.
C++ Code
#include <bits/stdc++.h>
using namespace std;
int main()
{
int year;
year=2000;
if(year % 400 == 0)
cout << year << " is a Leap Year";
else if(year % 4 == 0 && year % 100 != 0)
cout << year << " is a Leap Year";
else
cout << year << " is not a Leap Year";
return 0;
}Output
2000 is a Leap Year
Method 2: Using if-else Statements 2
In this method we’ll use the if-else statements to check for the above mentioned conditions one by one. This method is the more simplified version of the previous method.
Working
For user input year check –
- If (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
- Print Leap Year
- Else, year will be not leap
Let’s implement the above logic in C++ Language.
C++ Code
#include<bits/stdc++.h>
using namespace std;
int main()
{
int year;
year=2000;
if(year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
cout << year << " is a Leap Year";
//not leap year
else
cout << year << " is not a Leap Year";
return 0;
}Output
2000 is a Leap Year
Method 3: Using Ternary Operator
In this method we’ll use the Ternary operator to check for the above mentioned conditions. For more information on Ternary operators check out Ternary operators in C.
Working
For user input year check
- Using ternary operator check if the year is divisible by 400. Print it’s a leap year.
- Using Ternary operator check if the year is divisible by 4 but not with 100. Print it’s a leap year.
- Else print it’s not a leap year.
Let’s implement the above mentioned logic in C++ Language.
C++ Code
#include
using namespace std;
int main()
{
int year;
year=2000;
int flag = (year%400 == 0) || (year%4==0 && year%100!=0 ) ? 1 : 0;
if (flag ==1)
{
printf("%d is a Leap Year",year);
}
else
{
printf("%d is not a Leap Year",year);
}
return 0;
}
Output
2000 is a Leap Year
Method 4: Complicated if-else statements
Some websites have also mentioned the below program as well, which is we why are just showing you the below, however, this is complicated to understand and code also we do not recommend writing this program below –
#include <iostream>
using namespace std;
int main() {
int year;
year=2000;
if (year % 4 == 0) {
if (year % 100 == 0) {
if (year % 400 == 0) {
cout << year << " is a Leap Year";
}
else {
cout << year << " is not a Leap Year";
}
}
else {
cout << year << " is a Leap Year";
}
}
else {
cout << year << " is not a Leap Year";
}
return 0;
}
Output
2000 is a Leap Year
Prime Course Trailer
Related Banners
Get PrepInsta Prime & get Access to all 200+ courses offered by PrepInsta in One Subscription
- Positive or Negative number: C | C++ | Java | Python
- Even or Odd number: C | C++ | Java | Python
- Sum of First N Natural numbers: C | C++ | Java | Python
- Sum of N natural numbers: C | C++ | Java | Python
- Sum of numbers in a given range: C | C++ | Java | Python
- Greatest of two numbers: C | C++ | Java | Python
- Greatest of the Three numbers: C | C++ | Java | Python
- Leap year or not: C | C++ | Java | Python
- Prime number: C | C++ | Java | Python
- Prime number within a given range: C | C++ | Java | Python
- Sum of digits of a number: C | C++ | Java | Python
- Reverse of a number : C | C++ | Java | Python
- Palindrome number: C | C++ | Java | Python
- Armstrong number : C | C++ | Java | Python
- Armstrong number in a given range : C | C++ | Java | Python
- Fibonacci Series upto nth term : C | C++ | Java | Python
- Find the Nth Term of the Fibonacci Series : C | C++ | Java | Python
- Factorial of a number : C | C++ | Java | Python
- Power of a number : C | C++ | Java | Python
- Factor of a number : C | C++ | Java | Python
- Strong number : C | C++ | Java | Python
- Perfect number : C | C++ | Java | Python
- Automorphic number : C | C++ | Java | Python
- Harshad number : C | C++ | Java | Python
- Abundant number : C| C++ | Java | Python
- Friendly pair : C | C++ | Java | Python
Login/Signup to comment
#include
using namespace std;
int main()
{
int year;
cin>>year;
if(year%4==0){
if(year%100==0){
if(year%400==0){
cout<<"Leap Year";
}
else
cout<<"Not Leap Year";
}
else
cout<<"Leap Year";
}
else
cout<<"Not Leap Year";
return 0;
}