InfyTQ Logical Deduction Quiz 3

Option(B) Explanation The first and the last letters are interchanged and the 2 nd and 4 th letter is added by 1 and 3 rd letter is subtracted by 1. On interchanging the 1 st and last letter the word CHIME will become EHIMC, the on adding and subtracting the letter the word will become EIHNC.

Option(B) Explanation The first and third letter remains the same. 2 nd and 3 rd are interchanged. 4 th and 7 th is interchanged and lastly, 5 th and 6 th is interchanged. Therefore, the code for the word FORTUNER will be FROENUTR.

Option(C) Explanation The first letter in the word BLISS, which is B, is added by 2, L is added by 4, I is added by 8, S is added by 16, and the last letter remains the same. Thus, the same thing will be done with the word ENTER. E is added by 2, N is added by 4, T is added by 8, E is added by 16 and R will remain the same. Therefore, the word will be GRBUR.

Option(A) Explanation On placing Z as 1 and A as 26 the value of the letters will be reversed. P is at 16 th place so if we count from back at 16 th place the letter will be K. Similarly, the word the letters in the word reward R is at 18 th place so from backward the letter at 18 th place is I, E is V, W is D, A is Z, R is I, and D is W. So the word is IVDZIW.

Option(A) Explanation

It is clear from the above illustration that the code for WINDOWS is XHPBRTW.

Option(B) Explanation In the word FIND the 1 st and last letter is added by 2 and the 2 nd and 3 rd letter remains the same. Similarly, in the word GANG G will become I, A will remain A, N will remain N, and G will become I. So, the word is IANI.

Option(B) Explanation

 

Option(C) Explanation The place of S in all the alphabets is 19, I is 9, and N is 14. Similarly, the place of D in all the alphabets is 4, A is 1, and M is 13. So the code is 4113.

Option(B) Explanation The place of O in all the alphabets is 15 and the place of F is 6. On adding 15 + 6 we get 21. The place of A in all the alphabets is 1 and the place of T is 20. So 20 + 1 = 21.