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Solution:

Considering the points to be A, B, C, and D,

The midpoint of AC = Midpoint of BD

\frac{x+1}{2} , \frac{6+2}{2} = \frac{4+3}{2}, \frac{y+5}{2}

⇒ \frac{x+1}{2} = \frac{7}{2} and \frac{6+2}{2} = \frac{y+5}{2}

X+1 = 7 and 8 = y+5

X= 6, and y = 3

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