# InfyTQ Algebra Quiz 1

Question 1

Time: 00:00:00
If x3 + y3 = 18 and x + y = 6, then the value of x4+y4 is,

-100

-100

-14

-14

44

44

-46

-46

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Question 2

Time: 00:00:00
L&T Pvt. Ltd. produces 1200 JCB every day. If out of these, $2 \frac{1}{3}$ faulty and $4 \frac{1}{3}$ are defective in packaging. Then how many non-faulty and non-defective packaged JCB are produced every day?

80

80

120

120

1080

1080

1120

1120

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Question 3

Time: 00:00:00
Alia Bhatt solved the following question in her Mathematics Examination $\frac{\frac{6}{4} + 5\frac{1}{6} \text{ of } \frac{3}{7}}{5 + 2 \frac{1}{3}}$ and her answer was $\frac{38}{77}$. By how much was her answer wrong?

1

1

$\frac{1}{77}$

$\frac{1}{77}$

$\frac{2}{77}$

$\frac{2}{77}$

$\frac{39}{77}$

$\frac{39}{77}$

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Question 4

Time: 00:00:00
$(\frac{3}{10})^{-8} \times (\frac{10}{3})^{-2}=(\frac{3}{10})^{x}$

3

3

6

6

-6

-6

2

2

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Question 5

Time: 00:00:00
$\frac{(x^{2} - y^{2})}{(x-y)^{2}} = 4$ and x = 8 then y = ?

$\frac{22}{5}$

$\frac{22}{5}$

$\frac{23}{5}$

$\frac{23}{5}$

$\frac{24}{5}$

$\frac{24}{5}$

$\frac{34}{5}$

$\frac{34}{5}$

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Question 6

Time: 00:00:00
Find the value of x: $\frac{0.006}{x}$ = 0.01

6

6

60

60

0.6

0.6

0.006

0.006

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Question 7

Time: 00:00:00
A person goes to a company’s cashier window for the refund and Quotes A Rs and B paise on a cheque. The cashier misreads it and gives B Rs and A paise. The woman comes out and donates 5 paise to a beggar. Now, the woman has exactly double the amount she has quoted on the cheque. Then find the amount the woman quoted on the cheque.

35 Rs and 65 paise

35 Rs and 65 paise

32 Rs and 63 paise

32 Rs and 63 paise

30 Rs and 65 paise

30 Rs and 65 paise

31 Rs and 63 paise

31 Rs and 63 paise

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Question 8

Time: 00:00:00
Sugarcane in the field grows equally thick and at a uniform rate. It takes 24 days for 70 workers and 60 days for 30 workers to cut the sugarcane. How many workers can cut the same in 96 days?

18

18

20

20

21

21

19

19

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Question 9

Time: 00:00:00
$(\frac{ x }{ y})^{a-1} = (\frac{ y }{ x})^{a-3}$ then the value of a?

1

1

2

2

0.5

0.5

4

4

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Question 10

Time: 00:00:00
The relationship after removing a, b and c from a + b = x, b + c = y, c + a = z and a + b + c = n is:

n = a + b + c

n = a + b + c

2n = x + y + z

2n = x + y + z

m = a - b -c

m = a - b -c

2n = a - b –c

2n = a - b –c

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