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Palindromic Partitions of the given String in Python
Here on this page, We will learn How to Find All Possible Palindromic Partitions of the given String in Python Programming Language. We will discuss both approach and code on this page.


Algorithm
- We go through every substring starting from the first character
- Check if it is a palindrome
- If yes, then add the substring to the solution
- And recur for the remaining part


Python Code
Run
def isPalindrome(str, low, high): while low < high: if str[low] != str[high]: return False low += 1 high -= 1 return True def allPalPartUtil(allPart, currPart, start, n, str): if start >= n: x = currPart.copy() allPart.append(x) return for i in range(start, n): if isPalindrome(str, start, i): currPart.append(str[start:i + 1]) allPalPartUtil(allPart, currPart, i + 1, n, str) currPart.pop() def allPalPartitions(str): n = len(str) allPart = [] currPart = [] allPalPartUtil(allPart, currPart, 0, n, str) for i in range(len(allPart)): for j in range(len(allPart[i])): print(allPart[i][j], end=" ") print() string = "nitin" allPalPartitions(string)
Output
n i t i n
n iti n
nitin
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