# Python Program for Octal To Binary Conversion

## Octal To Binary Conversion in Python

Here, in this page we will discuss the program for octal to binary conversion in Python . Numbers with base 8 are called octal numbers and uses digits from 0-7 for representation of octal number. Where as numbers with base 2 are called binary numbers  and it uses 0 and 1 for representation of binary numbers. ## Method 1:-

• Accept octal number
• Convert it into decimal Equivalent
• Convert this decimal value into Binary

Make sure you have visited these two pages before moving ahead with the code –

### Method 1 Code in Python

Run
```def convert(octal):
i = 0
decimal = 0
while octal != 0:
digit = octal % 10
decimal += digit * pow(8, i)
octal //= 10
i += 1
print("Decimal Value :", decimal)
binary = 0
rem = 0
i = 1

while decimal != 0:
rem = decimal % 2
decimal //= 2
binary += rem * i
i *= 10
print("Binary Value :", binary)

octal = int(input("Octal Value : "))
convert(octal)
```

### Output

`Octal Value: 12Decimal Value: 10Binary Value: 1010`

## Method 2

Each digit of an octal number can be converted into its binary Equivalent (see image)

### Binary Representation for Octal digit:

• 0 => 000
• 1 => 001
• 2 => 010
• 3 => 011
• 4 => 100
• 5 => 101
• 6 => 110
• 7 => 111 ### Method 2 Code in Python

Run
```def convert(octal):
print("Equivalent Binary Number: ", end="")
for i in range(len(octal)):
switcher = {
0: "000",
1: "001",
2: "010",
3: "011",
4: "100",
5: "101",
6: "110",
7: "111"
}
print(switcher.get(int(octal[i]), "Invalid Octal Number"), end="")

octal = list(input("Insert an octal number: "))
convert(octal)
```

### Output

`Insert an octal number: 347Equivalent Binary Number: 011100111`

### 2 comments on “Python Program for Octal To Binary Conversion”

• Sonal

num=int(input(“Enter the octal value “))
temp=num
bin_val=0
deci_val=0
base1=1
base2=1
while(temp):
digit=temp%10
deci_val+=digit*base1
base1*=8
temp//=10
while(deci_val):
rem=deci_val%2
bin_val+=rem*base2
base2*=10
deci_val//=2
print(“The binary value of {} is {}”.format(num,bin_val)) 0
• M D

We input is provided by user:
code——————->
def conv_oct_to_b(n):
return bin(n)
if __name__==’__main__’:
n = int(input(“Enter a binary number : “),8)
print(conv_oct_to_b(n)) 0