Python Program for Octal To Binary Conversion

September 30, 2022

Octal To Binary Conversion in Python

Here, in this page we will discuss the program for octal to binary conversion in Python . Numbers with base 8 are called octal numbers and uses digits from 0-7 for representation of octal number. Where as numbers with base 2 are called binary numbers  and it uses 0 and 1 for representation of binary numbers.

Algorithm for octal to binary conversion

Method 1:-

  • Accept octal number
  • Convert it into decimal Equivalent
  • Convert this decimal value into Binary

Make sure you have visited these two pages before moving ahead with the code –

Method 1 Code in Python

Run 
def convert(octal):
    i = 0
    decimal = 0
    while octal != 0:
        digit = octal % 10
        decimal += digit * pow(8, i)
        octal //= 10
        i += 1
    print("Decimal Value :", decimal)
    binary = 0
    rem = 0
    i = 1

    while decimal != 0:
        rem = decimal % 2
        decimal //= 2
        binary += rem * i
        i *= 10
    print("Binary Value :", binary)


octal = int(input("Octal Value : "))
convert(octal)

Output

Octal Value: 12
Decimal Value: 10
Binary Value: 1010

Decimal to Binary conversion

Decimal to Octal Conversion

Decimal to Hexadecimal Conversion

Permutations in which n people can occupy r seats in a classroom 

Octal to Binary conversion

Quadrants in which a given coordinate lies

Method 2

Each digit of an octal number can be converted into its binary Equivalent (see image)

Binary Representation for Octal digit:

  • 0 => 000
  • 1 => 001
  • 2 => 010
  • 3 => 011
  • 4 => 100
  • 5 => 101
  • 6 => 110
  • 7 => 111
Octal to Binary in C Program

Method 2 Code in Python

Run 
def convert(octal):
    print("Equivalent Binary Number: ", end="")
    for i in range(len(octal)):
        switcher = {
            0: "000",
            1: "001",
            2: "010",
            3: "011",
            4: "100",
            5: "101",
            6: "110",
            7: "111"
        }
        print(switcher.get(int(octal[i]), "Invalid Octal Number"), end="")


octal = list(input("Insert an octal number: "))
convert(octal)

Output

Insert an octal number: 347
Equivalent Binary Number: 011100111

Prime Course Trailer

Related Banners

Get PrepInsta Prime & get Access to all 200+ courses offered by PrepInsta in One Subscription

Get Prime

3 comments on “Python Program for Octal To Binary Conversion”


  • D

    n=int(input())
    s=0
    base=0
    while(n!=0):
    r=n%10
    s+=(r*(8**base))
    base+=1
    n=int(n/10)
    print(“decimal number is”,s)

    #decimal to binary
    a=[]
    while(s>0):
    q=s%2
    a.append(q)
    s=int(s/2)
    for i in reversed(a):
    print(i,end=”)

    0

  • Sonal

    num=int(input(“Enter the octal value “))
    temp=num
    bin_val=0
    deci_val=0
    base1=1
    base2=1
    while(temp):
    digit=temp%10
    deci_val+=digit*base1
    base1*=8
    temp//=10
    while(deci_val):
    rem=deci_val%2
    bin_val+=rem*base2
    base2*=10
    deci_val//=2
    print(“The binary value of {} is {}”.format(num,bin_val))

    0

  • M D

    We input is provided by user:
    code——————->
    def conv_oct_to_b(n):
    return bin(n)
    if __name__==’__main__’:
    n = int(input(“Enter a binary number : “),8)
    print(conv_oct_to_b(n))

    0