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Python program for decimal to octal conversion
Decimal to octal conversion
Here, in this section we will discuss the program for decimal to octal conversion in python. Decimal numbers are the standard representation for representing integer or non-integer values. Decimal numbers are with base 10 and can represent numbers from 0-9. Whereas in Octal representation of numbers, numbers from 0-7 are represented as octal numbers are with base 8.
Methods Discussed:-
- Using an array to store the comparable octal value
- Using int variable to store comparable octal value
Algorithm ( Method 1 )
- Take the decimal number from the user and store it in variable say decimal.
- Create an array say octal to store the octal representation of the given decimal number.
- Run a loop until decimal is not equal to 0 i.e., (decimal !=0)
- Inside the loop insert the remainder that achieved by dividing decimal from 8 i.e., (decimal%8)
- Coming out from the loop print the octal array in reverse order.
Python Code
Run
decimal = 148 octal = [] while decimal > 0: r = decimal % 8 octal.append(r) decimal = decimal // 8 for i in reversed(octal): print(i, end="")
Output
224
Algorithm ( Method 2 )
- Initialize ocatalNum to 0 and countVal to 1 and the decimal number as n
- Find the remainder when decimal number divided by 8
- Update octal number by octalNum + (remainder * countval)
- Increase countval by countval*10
- Divide decimal number by 8
- Repeat from the second step until the decimal number is zero
Python Code
Run
decimal = 33 octal = 0 count = 1 while decimal > 0: r = decimal % 8 octal += r * count count *= 10 decimal = decimal // 8 print(octal)
Output
41
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num=int(input(“Enter the decimal number “))
sum=0
temp=num
base=1
while(temp):
digit=temp%8
sum+=digit*base
base*=10
temp//=8
print(“The octal value of {} is {}”.format(num,sum))