Python program to count numbers of even and odd elements in an array

October 12, 2022

count even and odd elements in python

Count number of even and odd elements in Python

Here, in this page you will find the program to count number of even and odd elements in python programming language. We are given with an integer array and need to print the count of even elements and odd elements.

Here, we will discuss the following two methods to print the count of even elements and odd elements.

  • Method 1 : Using Modulo operator
  • Method 2 : Using Bit-wise AND operator.

Let’s discuss above two methods one by one,

Method 1 :

  • Take two variables, countEven=0, countOdd=0.
  • Iterate over the array,
  • Increment countEven if(arr[i]%2==0)
  • Otherwise increment the value of countOdd by 1.

Method 1 : Code in Python

Run 
arr = [1, 7, 8, 4, 5, 16, 8]
n = len(arr)
countEven = 0
countodd = 0
for i in range(0, n):
    if arr[i]%2==0 :
        countEven += 1
    else:
        countodd += 1

print("Even Elements count : " )
print(countEven)

print("Odd Elements count : ")
print(countodd)

Output :

Even Elements count :
4
Odd Elements count :
3

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Method 2 :

In this method we will use bit-wise AND operator. By doing AND of 1 with array element, if the result comes out to be 0 then the number is even otherwise odd.

Method 2 : Code in Python

Run 
arr = [1, 7, 8, 4, 5, 16, 8]
n = len(arr)
countEven = 0
countodd = 0
for i in range(0, n):
    if arr[i]&1==0 :
        countEven += 1
    else:
        countodd += 1

print("Even Elements count : " )
print(countEven)

print("Odd Elements count : ")
print(countodd)

Output :

Even Elements count :
4
Odd Elements count :
3

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6 comments on “Python program to count numbers of even and odd elements in an array”


  • sangramdhurve96

    arr = [1, 7, 8, 4, 5, 16, 8]
    ev = od = 0
    for i in range(0,len(arr)):
    if arr[i]%2==0:
    ev+=1
    else:
    od+=1
    print(f”Evens are {ev} and odds are {od}.”)


  • Bhavna

    array=list(map(int,input(“Enter a array”).split()))
    counteven=0
    countodd=0
    for i in array:
    if i%2==0:
    counteven+=i
    else:
    countodd+=i
    print(f”Even:{counteven}”)
    print(f”odd:{countodd}”)


  • yugander9010

    num = input().split(‘,’)
    ls=[int(item) for item in num]
    even=0
    odd=0
    even_nums=[]
    odd_nums=[]
    for i in range(len(ls)):
    if ls[i]%10==0:
    even+=1
    even_nums.append(str(ls[i]))
    else:
    odd+=1
    odd_nums.append(str(ls[i]))
    even_n=’ ‘.join(even_nums)
    odd_n=’ ‘.join(odd_nums)
    print(f”Even Elements count={even}({even_n})”)
    print(f”Even Elements count={odd}({odd_n})”)


  • Vikas Reddy Gorantla

    a=[1, 7, 8, 4, 5, 16, 8]
    even_count=0
    odd_count=0
    for i in a:
    if i%2==0:
    even_count+=1
    else:
    odd_count+=1
    print(even_count)
    print(odd_count)


  • Tanishka

    a = [1, 7, 8, 4, 5, 16, 8]
    c=0
    p=0
    for i in a:
    if(i%2==0):
    c+=1
    else:
    p+=1
    print(“even =”,c ,”odd =”, p)


  • abhishek

    arr = [1, 2, 6, 3, 7]

    n = len(arr)
    def f(arr,n):

    even , odd = 0,0
    for i in arr:
    if(i % 2 == 0):
    even += 1
    else:
    odd += 1
    print(even , odd)

    f(arr,n)