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HSBC Areas Questions and Answers Quiz-1

Question 1

Time: 00:00:00

The area of a triangle is with base 4m and height 5m?

20 sq m

10 sq m

5 sq m

3 sq m

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Explanation:

1/2 * 4 * 5 = 10 m²

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Question 2

Time: 00:00:00

The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:

15360

153600

30720

307200

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Explanation:

Perimeter = Distance covered in 8 min. =		12000	x 8	m = 1600 m.
		60

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.

Area = (480 x 320) m² = 153600 m².

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Question 3

Time: 00:00:00

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

2.02%

4.04%

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Explanation:

100 cm is read as 102 cm.

A₁ = (100 x 100) cm² and A₂ (102 x 102) cm².

(A₂ - A₁) = [(102)² - (100)²]

= (102 + 100) x (102 - 100)

= 404 cm².

Percentage error =		404	x 100	%	= 4.04%
		100 x 100

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Question 4

Time: 00:00:00

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

16 cm

18 cm

24 cm

Data Inadequate

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Explanation:

2(l + b)	=	5
b	=	1

2l + 2b = 5b

3b = 2l

b =	2	l
	3

Then, Area = 216 cm²

l x b = 216

l x	2	l	= 216
	3

l² = 324

l = 18 cm.

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Question 5

Time: 00:00:00

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:

40%

42%

44%

46%

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Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m².

New length =		120	x	m	=		6	x	m.
		100					5

New breadth =		120	y	m	=		6	y	m.
		100					5

New Area =		6	x x	6	y	m²	=		36	xy	m².
		5		5					25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % =		11	xy x	1	x 100	%	= 44%.
		25		xy

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Question 6

Time: 00:00:00

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

2.91 m

3 m

5.82 m

None of these

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Explanation:

Area of the park = (60 x 40) m² = 2400 m².

Area of the lawn = 2109 m².

Area of the crossroads = (2400 - 2109) m² = 291 m².

Let the width of the road be x metres. Then,

60x + 40x - x² = 291

x² - 100x + 291 = 0

(x - 97)(x - 3) = 0

x = 3.

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Question 7

Time: 00:00:00

The diagonal of the floor of a rectangular closet is 7

feet. The shorter side of the closet is 4

feet. What is the area of the closet in square feet?

5 1/4

13 1/2

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Explanation:

Other side

	15		2	-		9		2
	2					2

225	-	81
4	-	4

144

6 ft.

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

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Question 8

Time: 00:00:00

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

10%

10.08%

20%

28%

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Explanation:

Let original length = x and original breadth = y.

Decrease in area

= xy -		80	x	x	90	y
		100			100

=		xy -	18	xy
			25

=	7	xy.
	25

Decrease % =

xy x

x 100

= 28%.

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Question 9

Time: 00:00:00

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

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Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % =		0.59x	x 100	%	= 30% (approx.)
		2x

Video solution:

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Question 10

Time: 00:00:00

The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

9 cm

18 cm

20 cm

41 cm

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Explanation:

l² + b² = 41.

Also, lb = 20.

(l + b)² = (l² + b²) + 2lb = 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

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