First Naukri SI and CI Quiz 1

Ans: Let Madhu took Rs. a and Vikash took Rs. b

Let the rate of interest was r% per annum

They lent Rs. (a + b) to Nikhil at the rate of (r + 2)% per annum

For Madhu,

The total interest received on Rs a = a \times 4 \times \frac{(r+2)}{100}

The total interest paid by Madhu to the bank = a\times r \times \frac{4}{100}

The total interest earned by Madhu after paying the interest to the bank

a \times 4 \times \frac{(r+2)}{100} -  a\times r \times \frac{4}{100} = \frac{8a}{100} ------- (1)

For Vikash,

The total interest received on Rs. b = b \times 4 \times \frac{(r+2)}{100}

The total interest paid by Vikash to the bank = b\times r \times \frac{4}{100}

The total interest earned by Vikash after paying the interest to the bank

b \times 4 \times \frac{(r+2)}{100} -  b\times r \times \frac{4}{100} = \frac{8b}{100} ------- (2)

From the question,

a – b = 50 × 100 = Rs. 5000

Ans: Ratio of profit = 2000 : 900 = 20 : 9

Let the amount invested by Nikhil be K

Ratio of investment = 12 × 7200 : 6 × K = 14400 : K = 20 : 9

K = Rs 6480

Let original Salary of Nikhil = R

60 %( R) at 40% p.a for 6 months

\frac{60}{100} \times R \times \frac{40}{200} \times 1 = 6480 - 0.6R

R = Rs. 9000

Ans: Let the total investment in 2nd scheme be Rs.x, then

(49000 - x) \times \frac{5}{100} + x \times \frac{12}{100} = 4900

x= 35000

Ans: Let the amount of money Mallika had initially = Rs. x

Amount distributed between Rita and Mita = Rs. 0.65x

Amount received by Rita = 0.65x \times \frac{6}{13} = Rs.0.3 x

Amount received by Mita = 0.65x \times \frac{7}{13} = Rs.0.35 x

Interest earned by Mita = 0.35x × 0.08 × 5 = Rs.0.14 x

Interest earned by Rita = 0.3x × 0.07 × 5 = Rs.0.105 x

According to the question,

0.14x – 0.105x = 1890

0.035x = 1890

x = 54000

So, the amount left with Mallika = 0.35 × 54000 = Rs. 18900

Ans: According to the formula of Simple Interest

SI = \frac{P\times R\times T}{100}

​300 = \frac{P\times 5\times 2}{100}300

P =  Rs 3000

Ans: According to the question,

8250 × (x + 4) % × 4 – 8250 × 8% × 4 = 1320

330 (x + 4) – 2640 = 1320

330 (x + 4) = 3960

x + 4 = 12 ; x = 8

So, the value of x = 8%

Ans: CI for 2 years 6 months at the rate of 6, applying the net% effect for first 2 years = 6 + 6 + \frac{6 \times 6}{100} = 12.36%

Rate of interest for 6 months = \frac{6}{12} \times 6 = 3%

For next 6 months = 12.36 + 3 + \frac{12.36 \times 3}{100} = 15.73%

Here, we can see that in 2 years 6 months the given compound rate of interest is approximately 15.73%.

Now, 115.73% of 250000 = \frac{115.73 \times 250000}{100} = 289325

Ans: When compounded annually, the amount received at the end of the period is 

A = P \times [ 1 + \frac{r}{100}]^{n}

When compounded half yearly, the amount received at the end of the period is

A = P \times [ 1 + \frac{\frac{r}{2}}{100}]^{2n}

Let the principle be P.

Interest on this amount when compounded annually at the rate of 20% per annum = P [(1.20)^{2}− 1]

Interest on this amount when compounded half yearly = P [(1.10)^{4}− 1]

The difference between the two is Rs. 482

∴ P [(1.10)^{4}− 1] – P [(1.20)^{2}− 1] = 482

∴ P [1.4641 – 1.44] = 482

∴ P = Rs. 20,000

Ans: Let the sum be Rs. P.

S.I. = Rs. (900 – P)

50 P = 90000 – 100P

150 P = 90000

P = Rs. 600

Now, P = 600, R = 15%, T = 2.5years

S.I. = = Rs. 225

Hence, amount = 600 + 225 = Rs. 825

Ans: Simple interest earned from SBI mutual fund

=\frac{(14500 \times 9 \times 2)}{100} = Rs. 2610

Simple interest earned from Birla Sun Life mutual fund

= \frac{2610 \times 12 \times 5}{100} = Rs. 1566

Total simple interest earned = 2610 + 1566 = Rs. 4176