Table chart Questions and Answers

Students getting 40 and above marks = 70 + 40 + 35 = 145
Students getting 80 and above marks = 4 : 3 : 7 = 14
Students getting 40 and above marks but less than 80 marks = 145 – 14 = 131

Students getting 40 marks and above in Biology = 35
Students who get 60 marks and above in Hindi = 12
Students who get less than 60 marks in Hindi = 80 – 12 = 68
Required % = 35 * 100) / 68 = 51.47

Students getting 40 marks and above in Biology = 35

Required %= (35 * 100) / 80 =43.75

Students getting 20 and above in Hindi = 75
Students getting less than 20 = 80 – 75 = 5
Students getting 40 and above in Biology = 35
Students getting less than 40 = 80 – 35 = 45
Required ratio = 5 : 45 = 1 : 9

Students getting 60 marks and above in Hindi = 12
Students getting less than 60 marks in Hindi = 80 – 12 = 68
Students getting 60 marks and above in English = 18
Students getting less than 60 marks in English = 80 – 18 = 62
Students getting 60 marks and above in Biology = 15
Students getting less than 60 marks in Biology = 80 – 15 = 65

Average of total number of Job provided in Forest sector over the years

153311/5 = 30662.2

the average of total number of Job provided in RBI sector over the years

95496/5 = 19099.2

Required difference = 30662.2 – 19099.2 = 11563.2 = 11563.

The total number of Job provided in the DRDO sector in 2023= 6742

Total number of Job provided in all the sectors is 2023 = 28944
The required percentage =
= 6742 x 100/28944
= 23.29%

The Job in RBI sector by Congress government in 2024 = 5637

The Job in RBI sector by Congress government in 2023 = 5421
The required percentage
= ( 5637-5421 ) x (100/5421)
= 3.9% approx

The average number of Jobs provided in all sectors together in 2027

= 351162/6
= 58527

Job provided in the Police department in 2024 = 6210
Job provided in the RBI department in 2023 = 5421
The required percentage
= 6120 x (100/5421)
= 114.55% approximately

Following the common explanation, we get

The number of students who joined the school = 45 + 47 + 42 + 47 + 45 = 226

 

Following the common explanation, we get

Of the 46 students in part 1 in 2020, 39 got promoted to part 2 in 2021, i.e.,

(39 * 100 ) / 46 = 84.4 similar to 85

Following the common explanation, we get

Of the 46 students in part 2 in 2021, only 43 got promoted to part 3,i.e., 3 students failed.

Following the common explanation, we get

The total number of students who failed in part 1 from 2018 to 2021 = 3 + 4 + 7 + 5 = 19

Following the common explanation, we get

Number of students who joined from 2018 to 2020 = (45 + 47 + 42) = 134

Number of students who passed only by 2021 = (36 + 45) = 81

Reqd %= =60.44

Number of creta manufactured during 2017 to 2022
= (250 + 200 + 230 + 245 + 260 + 275)
= 1460

Number of alcazar manufactured during 2017 to 2022
= (200 + 230 + 225 + 210 + 135 + 155)
= 1155

Number kona manufactured during 2017 to 2022
= (128 + 150 + 142 + 170 + 180 + 230)
= 1000

Number of santro manufactured during 2017 to 2022
= (140 + 155 + 160 + 175 + 185 + 220)
= 1035

Number of venue manufactured during 2017 to 2022
= (115 + 120 + 135 + 125 + 130 + 120)
= 745

Thus, creta is manufactured in maximum number.

Production of creta in 2017 = 250
Production of creta in 2022 = 275

% increases= (275 - 250 / 250) * 100  = 10%

The table shows that the production of santro increases continuously over the years.

Production of venue in 2021 = 130
Production of alcazar in 2020 = 210

Reqd %= (130* 100) / 210 = 61.9

Production of santro in 2018
= 155 and that in 2020
= 175

Required difference
= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)
= 88.

Total number of Peons working in the Company in 2019
= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120) = 1192.

Number of Managers working in the Company:
In 2015 = 760.
In 2020 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.
Therefore, the Percentage increase in the number of Managers

(1252 - 760) / 760 * 100 = 64.74%

Number of Technicians working in the Company:
In 2015 = 1200.
In 2020 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.
Therefore, the Percentage increase in the number of Technicians

{(1936 - 1200 ) / 1200} * 100 = 61.33%

Number of Operators working in the Company:
In 2015 = 880.
In 2020 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.
Therefore, the Percentage increase in the number of Operators

(1444 - 880 / 880 ) * 100 = 64.09%

Number of Accountants working in the Company:
In 2015 = 1160.
In 2020 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.
Therefore, the Percentage increase in the number of Accountants

(1884 - 1160 / 1160 ) * 100 = 62.14%

Number of Peons working in the Company:
In 2015 = 820.
In 2020 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.
Therefore, the Percentage increase in the number of Peons

(1288 - 820 / 820 ) * 100 = 57.07%

Clearly, the percentage increase is maximum in the case of Managers.

Total number of employees of various categories working in the Company in 2017 are:
Managers = (760 + 280 + 179) - (120 + 92) = 1007.
Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.
Operators = (880 + 256 + 240) - (104 + 120) = 1152.
Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.
Peons = (820 + 184 + 152) - (96 + 88) = 972.
Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)
= 1/5 x (5975)
= 1195.

Total number of Operators who left the Company during 2015 - 2020
= (104 + 120 + 100 + 112 + 144)
= 580.
Total number of Operators who joined the Company during 2015 - 2020
= (880 + 256 + 240 + 208 + 192 + 248
= 2024.
Therefore, Required Percentage
= (580/2024)x100% = 28.66% ~= 29%.

Number of students who passed half-yearly exams in the school
= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76) = 288.
Also, the Number of students who passed annual exams in the school
= (Number of students who failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)
= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76) = 288.
Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level. Thus Statements (a), (b), and (d) are false and Statement (c) is true.

Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:
= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)
= 430.