# Maruti Suzuki Quiz on Equations with Answers

Question 1

Time: 00:00:00
Two packets are available for sale.

Packet a: peanuts 100 gms for Rs 48 only

Packet b: peanuts 150 gms for Rs 72 only

both have the same value

both have the same value

packet b

packet b

data insufficient

data insufficient

packet a

packet a

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Question 2

Time: 00:00:00
Consider the following two curves in the X-Y plane
y=(x3+x2+5)
y=(x2+x+5)
Which of the following statements is true for -2<= x <=2?

The two curves do not intersect.

The two curves do not intersect.

The two curves intersect thrice.

The two curves intersect thrice.

The two curves intersect twice.

The two curves intersect twice.

The two curves intersect once.

The two curves intersect once.

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Question 3

Time: 00:00:00
If $x + \frac{1}{x}$=4, the value of $x^{5} + \frac{1}{x^{5}}$ is:

724

724

500

500

752

752

525

525

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Question 4

Time: 00:00:00
For what value of “k” will the equation (2kx2 + 5kx +2)=0 have equal roots?

2/7

2/7

9/4

9/4

16/25

16/25

7/18

7/18

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Question 5

Time: 00:00:00
if x=12, y=4, then find the values of $(x+y)^\frac{x}{y}$

8009

8009

4096

4096

none

none

1024

1024

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Question 6

Time: 00:00:00
The number which should be subtracted from 5a2-3ab+7b2 to make it equal to a2+ab+b2 is

4a2-4ab+6b2

4a2-4ab+6b2

4a2-4ab+5b2

4a2-4ab+5b2

4a2+4ab+6b2

4a2+4ab+6b2

4a2-3ab+6b2

4a2-3ab+6b2

None of the above

None of the above

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Question 7

Time: 00:00:00
Evaluate: log(a2bc3)5

32log a + 5log b + 243log c

32log a + 5log b + 243log c

10log a + 5log b + 15log c

10log a + 5log b + 15log c

15(log a + log b + log c)

15(log a + log b + log c)

5log (a^2bc^3)

5log (a^2bc^3)

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Question 8

Time: 00:00:00
If r = at2 and s = 2at, then the relation among s, r and a is:

s= 2r/t

s= 2r/t

s = ar

s = ar

s2 = ar

s2 = ar

None of the above

None of the above

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Question 9

Time: 00:00:00
If $2^{x}\times 3^{y} = 18 \text{ and } 3^{y} = 36$, the value of x is :

-1

-1

2

2

3

3

1

1

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Question 10

Time: 00:00:00
What is the value of x + y in the solution of the equations?

(x / 4) + (y / 3) = (5 / 12) and (x / 2) + y = 1 is:

1/3

1/3

2

2

3/2

3/2

5/2

5/2

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