# Reverse an Array in Java

## Reverse an Array in Java

Here, in this page we will discuss the program to reverse an array in java. We are given with an array and need to print that array in reverse order. Here we will discuss different approaches to reverse the given input array.

Here, in page we will discuss various method for reversing the array. Different methods are :

## Method Discussed

• Method 1: Just print the array in reverse order
• Method 2: Actual in-place reversing of the original array
• Method 3: Recursive in-place reversing of the original array

### Example :

• Input : arr[5] = [10, 20, 30, 40, 50]
• Output : Array after reversing, arr[5] = [50, 40, 30, 20, 10]

## Method 1

• Run an iterative loop from the last index of the array
• Print each item one by one arr[i]

### Method 1 : Java Code

Run
```import java.util.Scanner;

public class Main
{
public static void main(String args[])
{

int arr[] = {10, 20, 30, 40, 50};

int n=arr.length;
for(int i=n-1; i>=0; i--)
System.out.print(arr[i]+" ");
}
}```

### Output:

`50 40 30 20 10`

## Method 2

• Take two variables start=0 and end=n-1
• Swap items at start & end indexes
• Do start++ & end–
• Stop when start & end indexes overlap one another
• Print the array

#### Time and Space Complexity :

• Time – Complexity : O(n)
• Space-Complexity : O(1)
•

### Method 2 : Java Code

Run
```import java.util.Scanner;

public class Main
{
public static void main(String args[])
{

int arr[] = {10, 20, 30, 40, 50};

int n=arr.length;
int start = 0, end = n-1;

while(start<end){
int temp = arr[start];
arr[start]=arr[end];
arr[end]=temp;
start++;
end--;
}
for(int i=0; i<n; i++)
System.out.print(arr[i]+" ");
}
}```

### output :

`50 40 30 20 10`

## Method 3

Initially pass values of start = 0, end = n – 1

• Function gets called as reverseRecursive(arr, 0, len-1);
• In each recursive iteration swap arr[start] & arr[end]
• Make further recursive calls as reverseRecursive(arr, start + 1, end – 1);
• return when (start >= end)
• Print the array

#### Time and Space Complexity :

• Time – Complexity : O(n)
• Space-Complexity : O(n), require stack to store the recursive calls

### Method 3 : Java Code

Run
```import java.util.Scanner;

public class Main
{
static void reverseRecursive(int arr[], int start, int end)
{
if (start >= end)
return;

int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;

// recursive call to swap arr[start+1] & arr[end-1]
reverseRecursive(arr, start + 1, end - 1);
}
public static void main(String args[])
{

int arr[] = {10, 20, 30, 40, 50};

int n=arr.length;
int start = 0, end = n-1;
reverseRecursive(arr, start, end);

for(int i=0; i<n; i++)
System.out.print(arr[i]+" ");
}
}```

### Output :

`50 40 30 20 10`

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