# Count the distinct elements in C++

Program to count the distinct elements  in C++, In this Program we will find out the elements which are unique in the array.

Given an integer array, we have to print all the distinct element of the input array. input array may contain duplicate elements, we have to print the count of elements that are distinct.

• Method 1 : Using Two loops
• Method 2 : Using hash Map

Let’s discuss each method one by one,

## Method 1 :

In this method we will count the frequency of each elements using two for loops.

• To check the status of visited elements create a array of size n and a variable say count_dis=0, to count the distinct element.
• Run a loop from index 0 to n and check if (visited[i]==1) then skip that element.
• Run a loop from index i+1 to n
• Check if(arr[i]==arr[j]), then set visited[j]=1.
• After complete iteration of inner for loop  increment the count_dis by 1.
• At last, print the value of count_dis.

### Time and Space Complexity :

• Time Complexity : O(n2)
• Space Complexity : O(n)

### Method 1 : Code in C++

Run
```#include <bits/stdc++.h>
using namespace std;

// Main function to run the program
int main()
{
int arr[] = {10, 30, 10, 20, 40, 20, 50, 10};
int n = sizeof(arr)/sizeof(arr[0]);

int visited[n], count_dis=0;

for(int i=0; i<n; i++){

if(visited[i]!=1){
for(int j=i+1; j<n; j++){
if(arr[i]==arr[j]){
visited[j]=1;
}
}
count_dis++;
}
}
cout<<count_dis;
return 0;
}```

`5`

## Method 2 :

In this method we will use hash-map to store the frequency of the elements.

• Create an unordered_map say mp and a variable say count_dis=0 to count the unique elements.
• Run a loop to iterate over array
• Set mp[arr[i]]++
• After, complete iteration,print the size of map, mp.size().

### Method 2 : Code in C++

Run
```#include <bits/stdc++.h>
using namespace std;

// Main function to run the program
int main()
{
int arr[] = {10, 30, 40, 20, 10, 20, 50, 10};
int n = sizeof(arr)/sizeof(arr[0]);

unordered_map <int, int>mp;
int count_dis=0;

for(int i=0; i<n; i++)
mp[arr[i]]++;

cout<<mp.size();
}```

`5`