Python program to Sort first half in ascending order and second half in descending order in an array

Sort First half in Ascending and Second half in descending order in Python

Sort First half in Ascending and Second half in descending order in Python

Here, in this page we will discuss the program to sort first half in ascending and second half in descending order in python programming language. We are given with an array and need to print the array in desired sorting way i.e, first half in increasing order and second half in descending order.

Here, in this page we will discuss two different methods to sort the given array such that it’s first half is in ascending order and second half in descending order.

  • Method 1 : Sort the entire array then, print first half in ascending and second half in descending.
  • Method 2 : Using alternative way of above method

Method 1 (Sort using inbuilt sort function):

  • Sort the entire array using inbuilt sort function
  • Run a loop till first half and print the element.
  • Run a loop for second half and print the elements.
sort the array in python

Method 1 : Code in Python

Run
# Python program to print first half in
# Python program to print first half in
# ascending order and the second half
# in descending order


# function to print half of the array in
# ascending order and the other half in
# descending order

def printOrder(arr,n) :
    # sorting the array
    arr.sort()
    
    # printing first half in ascending order
    i = 0
    while i < n/2: print(arr[i]) i=i+1 # printing second half in descending order j=n-1 while j >= n / 2 :
        print (arr[j])
        j = j - 1

# Driver code
arr = [5, 4, 6, 2, 1, 3, 8, 9, 7]
n = len(arr)

printOrder(arr, n)

Output

1 2 3 4  5 9 8 7 6 

Method 2 :

  • Sort the first half of the array in ascending order just because only the elements in the first half of the input array needs to be sorted in ascending order (In this way the original elements in the first half of the array will remain in the first half but in ascending order).
  • Sort the second half of the array in descending order just because only the elements in the second half of the input array needs to be sorted in descending order (In this way the original elements in the second half of the array will remain in the first half but in descending order)

Method 2 : Code in Python

Run
# Python 3 program to print first half
# in ascending order and the second half
# in descending order

# function to print half of the array in
# ascending order and the other half in
# descending order

def printOrder(arr, n):

    # sorting the array
    arr.sort()

    # printing first half in ascending order

    for i in range(n / 2):
        print(arr[i], end = " ")

    # printing second half in descending order

    for j in range(n - 1, n // 2 -1, -1) :
        print(arr[j], end = " ")

# Driver code
arr = [ 5, 4, 6, 2, 1, 3, 8, -1 ]
n = len(arr)
printOrder(arr, n)

Output

-1 1 2 3 8 6 5 4

Prime Course Trailer

Related Banners

Get PrepInsta Prime & get Access to all 200+ courses offered by PrepInsta in One Subscription

19 comments on “Python program to Sort first half in ascending order and second half in descending order in an array”


  • Utsav Pandey

    def find_element_frequency(arr):
    frequency_dict = {}

    for element in arr:
    if element in frequency_dict:
    frequency_dict[element] += 1
    else:
    frequency_dict[element] = 1

    return frequency_dict

    # Example usage:
    my_array = [1, 2, 2, 3, 3, 3, 4, 4, 4, 4]
    result = find_element_frequency(my_array)

    # Print the frequencies
    for element, frequency in result.items():
    print(f”Element {element} occurs {frequency} times”)


  • Yash

    aray=[3,2,4,5,6]
    aray=sorted(aray)
    print(aray)
    x=aray[int(len(aray)/2):]
    aray[int(len(aray)/2):]=reversed(x)
    print(aray)


  • Vindhya

    a=[5, 4, 6, 2, 1, 3, 8]
    a.sort()
    n=len(a)
    for i in range(0,int(n/2)):
    print(a[i],end=” “)
    a.sort(reverse=True)
    for j in range(0,int(n/2)):
    print(a[j],end=” “)


  • Nivedha

    arr2=[10,20,30,40,50,60]

    def half(arr):
    half1=sorted(arr)
    half2=arr[::-1]

    if len(arr)%2 ==0:
    leng=len(arr1)//2
    half1=half1[:leng]
    half2=half2[:leng]
    return half1+half2

    else:
    leng=len(arr1)//2
    half1=half1[:leng]
    half2=half2[:leng+1]
    return half1+half2

    arr1=[10,20,30,40,50,60]
    half(arr1)