Sort an array according to the order defined by another array in C

Method 1 : Code in C

#include<stdio.h>
 
int first(int arr[], int low, int high, int x, int n)
{
 
    if (high >= low) {
 
        int mid = low + (high - low) / 2;
 
        if ((mid == 0 || x > arr[mid - 1]) && arr[mid] == x)
            return mid;
 
        if (x > arr[mid])
            return first(arr, (mid + 1), high, x, n);
 
        return first(arr, low, (mid - 1), x, n);
    }
 
    return -1;
}
 
void sortAccording(int A1[], int A2[], int m, int n)
{
    int temp[m], visited[m];
    for (int i = 0; i < m; i++) {
        temp[i] = A1[i];
        visited[i] = 0;
    }
    
    for(int i=0; i<m; i++){
        for(int j=i+1; j<m; j++){ if(temp[i]>temp[j]){
                int x= temp[i];
                temp[i]= temp[j];
                temp[j]=x;
            }
        }
    } 
    
    int ind = 0;
 
    for (int i = 0; i < n; i++) {
        int f = first(temp, 0, m - 1, A2[i], m);
 
        if (f == -1)
            continue;
 
        for (int j = f; (j < m && temp[j] == A2[i]); j++) {
            A1[ind++] = temp[j];
            visited[j] = 1;
        }
    }
 
    for (int i = 0; i < m; i++)
        if (visited[i] == 0)
            A1[ind++] = temp[i];
}
 
void printArray(int arr[], int n)
{
 
    for (int i = 0; i < n; i++)
        printf("%d ", arr[i]);
        
    printf("\n");
}
 
// Driver Code
int main()
{
    int arr1[] = { 20, 1, 20, 5, 7, 1, 9, 39, 6, 18, 18 };
    int arr2[] = { 20, 1, 18, 39 };
    int m = sizeof(arr1) / sizeof(arr1[0]);
    int n = sizeof(arr2) / sizeof(arr2[0]);
 
    sortAccording(arr1, arr2, m, n);
    printArray(arr1, m);
    return 0;
}