Percentages Quiz-1

Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
Required percentage=\left ( \frac{50}{110}\times 100 \right )%= 45(5/11)%

Let their marks be (x + 9) and x.
Then, x + 9 =\frac{56}{100}\left ( x+9+x \right )
x=33
So, their marks are 42 and 33

Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required percentage =\left ( \frac{14}{70}\times 100 \right )%=20%

\text{ x % of y }=\left ( \frac{x}{100}\times y \right )=\left ( \frac{y}{100}\times x \right )=\text{ y % of x }
Therefore A=B

Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550
z+\frac{120}{100}z=550

z=250

Let the amount taxable purchases be Rs. x.
Then, 6% of x =30/100
x=5
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

No. of Characters in one line = 65
No. of characters in one sheet = No. of lines × No. of characters per line = 55 × 65
Total number of characters = No. of sheets × No. of characters in one sheet = 20 × 55 × 65 = 71500
If the report is retyped –
New sheets have 65 lines, with 70 characters per line
No. of characters in one sheet = 65 × 70
Number of pages required,
=(total number of characters)/(No. of characters in one sheet if retyped)=71500/(65*70)=15.71
Hence, 16 pages will be required if report is retyped

Hence, reduction of (20 – 16) = 4 pages
% reduction is = (4/20) x 100 = 20%

The person can buy 50 oranges or 40 mangoes.
Let the price of one orange be Rs. x
Total amount the person has = Rs. 50x
40 mangoes cost 50x, So one mango costs 1.25x
10% of the total amount is retained for taxi fare = 10% of 50x = 5x
20 mangoes bought for 20 x 1.25x = 25x
Money left with the person = 50x – (Taxi fare) – (Mangoes cost)
= 50x – 5x – 25x = 20x
One Orange was for Rs. x, Therefore, 20 oranges can be bought with Rs. 20 x
Thus, the person bought 20 oranges.

Let the total number of employees in the company be x

Then the number of men and women be 0.4x and 0.6x respectively.

75% of men earn more than Rs. 25000 => 0.75 x 0.4 x = 0.3 x

Total number of employees earning more than Rs. 25000 = 45% x = 0.45 x

Number of women earning more than Rs. 25000 =

Total employees earning more than Rs. 25000 – total number of Men earning more than Rs. 25000

= 0.45 x – 0.30 x = 0.15 x

Number of the women earning Rs. 25000 or less = 0.60 x – 0.15 x = 0.45 x

Fraction of the women employed by the company who earn Rs. 25000 or less

(0.45x/0.60x) = 45/60 = 3/4

Let number of girls in class A = x
Let number of boys in class A = y
Total number of students = x + y
Proportion of girls =\frac{x}{x+y}

Number of boys in class B = x
Total number of students in class B = 1.5(x + y)
Proportion of girls =1-\frac{x}{1.5\left ( x+y \right )}

percentage of boys in the overall student community = \frac{x+y}{2.5}*\left ( x+y \right )*100=40%

The question is " What percentage of the student group are boys? "
40% of the student group are boys
Hence, the answer is 40%
Choice B is the correct answer