# Replace All 0’s With 1 In A Given Integer | C Program

## Program to Replace all 0’s with 1 in a given integer

Here we will discuss how to replace all the 0’s with 1 in a given integer using C programming language.

The concept is simple, find the digits of the integer. Compare each digit with 0 if the digit is equal to 0 then replace it with 1. Construct the new integer with the replaced digits.

The program for Implement a C Program to replace all 0’s with 1 in a given integer as an input, all the 0’s in the number has to be replaced with 1.

### Algorithm

• Take Input in num and initialize a variable num with with value 0
• If num is equals to zero then update the value of num2 to 1
• Iterate using a while loop until num is greater then 0
• For each iteration initialize a variable rem and store unit digit of num
• If rem equals to 0 then set rem to 1
• Set num to num divide by 10 & num2 equals to num2*10+rem
• Reverse and print num2

### C code

Run
```#include<stdio.h>

//main program

int main()

{

int num,num2=0;

printf("Enter number: ");

//user input

scanf("%d", &num);

//checking for 0 input

if(num == 0)

num2=1;

//converting 0 to 1

while(num>0)

{

int rem = num%10;

if(rem == 0)

rem = 1;

num = num/10;

num2=num2*10+rem;

}

num = 0 ; // Store the reverse of num2

while(num2>0){

int r = num2%10;

num= num*10 + r;

num2 /= 10;

}

//converted number

printf("Converted number is: %d" ,num);

return 0;

}```

### Output

```Enter number: 900120678
Converted number is: 911121678```

### 17 comments on “Replace All 0’s With 1 In A Given Integer | C Program”

• 18-558

#include
int main()
{
int s,base=1,sum=0,n;
scanf(“%d”,&n);
while(n>0){
s=n%10;
if(s==0)
{
s=1;
}
n=n/10;
sum=sum+s*base;
base*=10;
}
printf(“%d”,sum);

}

• Shashi Kiran

#Solution in Python
def replace_0(num):
temp = ”
for i in str(num):
i = str(i)

if i == ‘0’:
temp += ‘1’
else:
temp += i
return int(temp)
Code complexity:
O(n) Time, O(n) space

• Gunaseelan

#include

int main() {
int n,r,d=0,i=1;
scanf(“%d”,&n);
if(n==0)
printf (“1”);
else
while (n>0)
{
r=n%10;
if(r==0)
{
r=1;
}
d=d+r*i;
n=n/10;
i=i*10;
}
printf (“%d”,d);
return 0;
}