C Code to Count Possible Decoding Of A Given Digit Sequence

September 30, 2022

Counting possible decoding of a given digit sequence in C

Here we will discuss how to count all the possible decoding of a given digit sequence in C. Before counting the number of decoding’s first let’s see how the numbers are assumed to be coded. The decoding programs are the most possible questions asked and are largely practiced in C  programming. The program counts the number of possible decoding’s of the entered digit by the user of the given sequence.

Possible decoding of a digit sequence in C

Explanation

1 = A, 2 = B, 3 = C, . . . . , 26 = Z.
The decoding programs are the most possible questions asked and are largely practiced in C  programming. The program counts the number of possible decoding’s of the entered digit by the user of the given sequence.
For example :- if the digit sequence is “12” then there are two possible decoding’s for this – One of them is ‘AB’ when we decode 1 as ‘A’ and 2 as ‘B’. Now we can also decode this digit sequence “12” as ‘L’ when we decode digits 1 and 2 taken together as an integer 12.

Now let’s take another example for reference,

Sequence = 131

  • Possible decoding (1, 3, 1,)    = ACA
  • Possible decoding (13, 1)   = MA
    So, the total possible decoding’s of sequence 131 is 2.

Algorithm

  • Initialize a array cnt of size 1 + length of input and store 1 at 0 & 1 position
  • Iterate from 2 to a using variable k
  • If the last digit not equal to 0, then last digit must added to the number of words if (dig[k-1] > ‘0’)
  • In case second last digit is smaller than 2 and last digit is smaller than 7, then last two digits form a valid character
  • Print cnt[a]
Possible decoding of a digit sequence

C code

Run 
//C Program to Count possible decodings of a given digit sequence
#include<stdio.h>
#include<string.h>
#include<math.h>

int cnt_decoding_digits(char *dig, int a)
{
    // Initializing an array to store results     
    int cnt[a+1]; 
    cnt[0] = 1;
    cnt[1] = 1;

    for (int k = 2; k <= a; k++) { cnt[k] = 0; // If the last digit not equal to 0, then last digit must added to the number of words if (dig[k-1] > '0')
            cnt[k] = cnt[k-1];

        // In case second last digit is smaller than 2 and last digit is smaller than 7, then last two digits form a valid character
        if (dig[k-2] == '1' || (dig[k-2] == '2' && dig[k-1] < '7'))
            cnt[k] += cnt[k-2];
    }
    return cnt[a];
}

int main()
{
    char dig[15];
    printf("\n Enter the sequence : ");
    gets(dig);
    int a = strlen(dig);
    printf("\n Possible count of decoding of the sequence : %d\n", cnt_decoding_digits(dig, a));
    return 0;
}

Output

Enter the sequence : 141
Possible count of decoding of the sequence : 2
 
 

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3 comments on “C Code to Count Possible Decoding Of A Given Digit Sequence”


  • lokeshharinath gontina

    num=int(input())
    val=[int(a) for a in str(num)]
    l=[]
    g=[]
    x=[]
    n=[]
    c=0
    k=0
    for i in val:
    l.append(i+64)
    for i in l:
    if(i>=65 and i=65 and i<=90):
    k=k+1
    s=c+k
    print(s)

    0

  • lokeshharinath gontina

    ”’code in python
    ”’
    num=int(input())
    val=[int(a) for a in str(num)]
    l=[]
    g=[]
    x=[]
    n=[]
    c=0
    k=0
    for i in val:
    l.append(i+64)
    for i in l:
    if(i>=65 and i=65 and i<=90):
    k=k+1
    s=c+k
    print(s)

    0

    • lokeshharinath gontina

      ”’

      Welcome to GDB Online.
      GDB online is an online compiler and debugger tool for C, C++, Python, Java, PHP, Ruby, Perl,
      C#, VB, Swift, Pascal, Fortran, Haskell, Objective-C, Assembly, HTML, CSS, JS, SQLite, Prolog.
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      ”’
      num=int(input())
      val=[int(a) for a in str(num)]
      l=[]
      g=[]
      x=[]
      n=[]
      c=0
      k=0
      for i in val:
      l.append(i+64)
      for i in l:
      if(i>=65 and i=65 and i<=90):
      k=k+1
      s=c+k
      print(s)

      0