Coding & Deductive logic Quiz-1

Explanation :

L + 2 = N; U + 2 = W; C + 2 = E; ......

Required answer is S + 2 = U; A + 2 = C; R + 2 = T; k + 2 = M;
UCTM

Explanation:
Here coding scheme can be seen to be as follows:

M - 26 - 13 = 13; I - 26 - 9 =17; S - 26-19 = 7; T - 26-20 = 6; E - 26 - 5= 21; R - 26 - 18 = 8.

Hence, in PAWAN we will have: P - 26-16=10; A - 26 - 1= 25; W - 26-23= 3;A - 26 - 1= 25;

N - 26 - 14 =12

Hence PAWAN = 102532512

Explanation:
Each letter in the word is moved one step ahead to obtain the corresponding letter.

Solution: In this question, the first three letters are reversed in the coded word, the next three letters are also reversed and the last three letters are also reversed. Thus, in PAR-AMP-ARA, PAR become RAP, AMP become PMA and ARA becomes ARA.

Similarly ;

SUD-HAK-ARA = DUS-KAH-ARA

R - 18th letter - 18 + 1 = 19; A - 1st letter - 1 + 1 = 2; M - 13th letter - 13 + 1 =14

RAM=  19214

Between the first and second sentences, the common word is hard and the common digit is 8. Hence , hard = 8. Between the first and the third sentences, the common word is study and the common digit is 6. Hence study = 6.

Hence, the code for 'very' can be found out to be '7'.

WORD       CODE

of                na

the                fu

selection        ju

maximum     fa

score              la

material        lu

study              ja

provide          hu

we                   ka

 

WORD       CODE

of                na

the                fu

selection        ju

maximum     fa

score              la

material        lu

study              ja

provide          hu

we                   ka

 

WORD       CODE

of                na

the                fu

selection        ju

maximum     fa

score              la

material        lu

study              ja

provide          hu

we                   ka

 

D is the 4th letter, E is the 5th , L is the 12th and so on. Hence, MUMBAI is equivalent to 132113219