Python Program for Printing Hollow Pyramid Star Pattern

Print Hollow Pyramid Star Pattern

Lets have a look at the program to hollow pyramid star pattern in python

We are going to discuss two methods below –

Method 1

Run
```row = 8

for i in range(row):
for j in range(row - i):
# prints left space in the same row
print(' ', end='')

for j in range(2 * i + 1):
# printing the left boundary of triangle
if j == 0:
print('*', end='')

# printing the right boundary of triangle
elif j == 2 * i:
print('*', end='')

# printing the bottom boundary of triangle
elif i == row - 1:
print('*', end='')

# printing spaces in the middle of the triangle
else:
print(' ', end='')

print()  # printing new line
```

Output

```        *
* *
*   *
*     *
*       *
*         *
*           *
***************```

Method 1.1

The above method can also be condensed down from multiple else if conditions to single as shown below –

Run
```row = 8

for i in range(row):
for j in range(row - i):
# prints left space in the same row
print(' ', end='')

for j in range(2 * i + 1):

# printing the left boundary of triangle
if j == 0 or j == 2 * i or i == row - 1:
print('*', end='')

# printing spaces in the middle of the triangle
else:
print(' ', end='')

print()  # printing new line
```

Output

```        *
* *
*   *
*     *
*       *
*         *
*           *
***************```

Method 2

Run
```num = 8
k = 0
for i in range(1, num + 1):
# printing left spaces in rows
for j in range(i, num):
print(" ", end="")

while k != (2 * i - 1):
# printing left/right boundaries
if k == 0 or k == 2 * i - 2:
print("*", end="")
# printing spaces in the middle of the triangle
else:
print(" ", end="")
k = k + 1

k = 0
print()

# printing bottom boundary of the triangle
for i in range(0, 2 * num - 1):
print("*", end="")
```

Output

```        *
* *
*   *
*     *
*       *
*         *
*           *
***************```

10 comments on “Python Program for Printing Hollow Pyramid Star Pattern”

#python
n=int(input())
sum=1
for i in range(n):
if(i==0 or i==n-1):
print(” “*(n-1-i)+”*”*sum)
else:
print(” “*(n-1-i)+”*”+” “*(sum-2)+”*”)
sum=sum+2

• Siva sankar reddy Asam

TRY THIS, IT’S WAY EASIER:
n = int(input(‘enter a number: ‘))

for i in range(0, n):
if i == 0:
print(‘ ‘*(n-1) + ‘*’)
elif i == n-1:
print(‘*’*(2*i+1))
else:
print(‘ ‘*(n-1-i) + ‘*’ + ‘ ‘*((i-1)*2+1) +’*’)

• Prasanth

n=5
f=5*2-1
for i in range(0,n):
if(i==0) or (i==n-1):
print(” ” * (1*i) , “\$” * (f-2*i) , sep=””)
else:
print(” “*(1*i),”\$”,” “*(f-(2*i)-2),”\$”,sep=””)

• Gowtham

n=n+1
for i in range(n,-1,-2):
print(” “,end=””)
print(” “*(i//2),end=””)
for p in range(0,n-i+1):
if(p==0):
print(“*”,end=””)
elif(p==n-i):
print(“*”,end=””)
else:
print(” “,end=””)
print(” “*(i//2),end=””)
print()
print(“*”*(n+3),end=””)

• 19-309-

inp = int(input())
j = 0
for i in range(inp):

if i == 0:
print( ((inp-i)*’ ‘) +’*’)
elif i == inp -1:
print( ((inp-i)*’ ‘) +( (i+1) + (j+1) ) * ‘*’)
else:
print( ((inp-i)*’ ‘) +’*’+ (i + j) * ‘ ‘ +’*’)
j = j + 1

n=int(input(“Entert the number: “))
for i in range(n):
for j in range(n-i):
print(” “,end=””)
for k in range(2*i+1):

# Condition of the if function
if k == 0 or k == 2 * i or i == n – 1:
print(“*”,end=””)
else:
print(” “,end=””)
print()

• Khushboo

n = int(input(“Enter the number:”))
for i in range(n):
if ((i==0) or (i==n-1)):
print(” “*(n-i) + (“*”)*(2*i+1))
else:
print(” “*(n-i) + (“*”) + (” “)*(2*i -1) + (“*”))

• mahesh

can solve even simply

num = int(input(“Enter the Number: “))
for i in range(0,num):
if i==0 or i==num-1:
print(” “*(num-i-1)+”*”*(i*2+1))
else:
print(” “*(num-i-1)+”*”+” “*(i*2+1-2)+”*”)

• Rahul

num = int(input(“enter number:”))

for i in range(1, num):
for j in range(0, num-i):
print(” “, end = ” “)
for j in range(0, (i*2)-1):
if((i > 0 and i 0 and j < (i*2)-2)):
print(" ",end = " ")
else:
print("*",end =" ")
print()