Python program to find non repeating characters in a string

October 14, 2022

Find Non Repeating Characters

The string is a combination of characters when 2 or more characters join together it forms string whether the formation gives a meaningful or meaningless output. In python programming, we treat a single character also as a string because there is no datatype as a character in python. In this python program, we will find unique elements or non repeating elements of the string.

Find Non Repeating Characters in python

Algorithm

  • Step 1:- store the string in a varaible lets say String.
  • Step 2:- lets it be “prepinsta”.
  • Step 3:- Start iterating through string.
  • Step 4:- Initialize count variable.
  • Step 5:- Again start iterating through same string.
  • Step 6:- Increment count variable as character is found in string.
  • Step 7:- If count is more then 2 break the loop.
  • Step 8:- If count is 1 print the character.
  • Step 9:- End.

Python Code:- Find Non Repeating Characters

#take user input
String = "prepinsta"
for i in String:
    #initialize a count variable
    count = 0
    for j in String:
        #check for repeated characters
        if i == j:
            count+=1
        #if character is found more than 1 time
        #brerak the loop
        if count > 1:
            break
    #print for nonrepeating characters
    if count == 1:
        print(i,end = " ")

Output

r e i n s t a
 
 

Toggle each character in a string

Count the number of vowels

Length of the string without using strlen() function

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21 comments on “Python program to find non repeating characters in a string”


  • nitesh

    s=input()
    d=””
    for i in s:
    fre=s.count(i)
    if fre>1:
    pass
    else:
    d+=i
    print(d)

    0

  • SUMAN

    s = input();
    d = {};
    for i in s :
    if i in d:
    d[i] += 1;
    else :
    d[i] = 1;
    for i in d.values() :
    if i == 1:
    print(d.keys());
    break;

    1

  • Altada

    str = input(‘Enter the string :’)
    x=list(dict.fromkeys(str))
    for i in x:
    if str.count(i)==1:
    print(i,end=””)

    0

  • Thanya

    s=str(input(“Enter the string:”))
    string=str()
    for i in s:
    if s.count(i)>1:
    pass
    else:
    string=string+i
    print(string)

    0

  • Ritik

    from collections import Counter
    s = input(‘Enter the string :’)
    s = Counter(s)
    for k in s:
    if s.get(k) == 1:
    print(k,end=” “)

    0

  • rajat

    n = input(“enter the string:”)
    for i in n:
    if n.count(i) == 1:
    print(i, end=”)

    0

  • RAVI

    s=input()
    for i in s:
    count=0
    if(s.count(i)>1):
    count=1
    else:
    count=0
    if(count==0):
    print(i,end=”)

    0

  • MAYANK

    // Here is my java program
    import java.util.HashMap;
    import java.util.Map;
    import java.util.Scanner;
    import java.util.Set;
    public class Program14 {

    static void foundUnique(String s1) {
    Map map = new HashMap();
    for (int i = 0; i < s1.length(); i++) {
    if (map.containsKey(s1.charAt(i)))
    map.put(s1.charAt(i), map.get(s1.charAt(i)) + 1);
    else
    map.put(s1.charAt(i), 1);
    }
    Set keys = map.keySet();
    for (Character ch : keys) {
    if (map.get(ch) == 1)
    System.out.print(ch + ” “);
    }
    }

    public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner sc = new Scanner(System.in);
    System.out.print(“Enter the String : “);
    String s1 = sc.nextLine();
    foundUnique(s1);
    }

    }

    3

  • Sankalp

    Another better approach:-
    st=”ChampakChacha”
    for i in st:
    if i!=” “:
    if (st.count(i)==1):
    print(i, end=” “)

    0
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