# Print Diamond Number Pattern Program Type 5

### 4 comments on “Print Diamond Number Pattern Program Type 5”

• prashant

//Easiest way
public class random
{
public static void main(String[] args)
{
int i,j,n=8,k=2,c=0;
for(i=1;i<=n;i++)
{
if(i<=n/2)
{
c=k;
for(j=1;j<=i;j++)
System.out.print(k++);
}
else
{
k=c;
for(j=1;j<=n-i+1;j++)
System.out.print(k++);
c=c-(n-i);
}
System.out.println();
}
}
}

• harsh

import java.util.*;
public class Main
{
public static void main(String[] args) {

int i,j,n;
Scanner in = new Scanner(System.in);
System.out.println(“Enter the rows: “);
n= in.nextInt();
int num=2;
for(i=1;i<=n;i++)
{
for(j=1;j=1;i–)
{
for(j=1;j<=i;j++)
{
System.out.print(temp);
temp++;
}

System.out.println();
num=num-(i-1);
temp=num;
}
}
}

• harsh

import java.util.*;
public class Main
{
public static void main(String[] args) {

int i,j,n;
Scanner in = new Scanner(System.in);
System.out.println(“Enter the rows: “);
n= in.nextInt();
int num=2;
for(i=1;i<=n;i++)
{
for(j=1;j=1;i–)
{
for(j=1;j<=i;j++)
{
System.out.print(temp);
temp++;
}

System.out.println();
num=num-(i-1);
temp=num;
}
}
}

• Karthik Murahari

public static void main(String[] args) {
int sum=2;
int sum1=8;
for (int i = 1; i <= 4; i++) {
for (int j = 1; j = 1; i–) {
for (int j = 1; j <= i ; j++) {
System.out.print(sum1+" ");
sum1++;
}
sum1 = (sum1/2)-1 ;
if(sum1==1){
sum1=2;
}
System.out.println();
}
}