# Given an integer N the task is to print the F(N)th term in C++

## Print F(N)th term in C++

Here, in this page we will discuss the program to print the F(N)th term in C++ Programming Language.  A function f is defined as follows F(N)= (1) +(2*3) + (4*5*6) … N. We are given with an integer N and we need to print the F(N)th term.

Example :

• Input : 4
• Output : 5167
• Explanation : 1 + (2*3) + (4*5*6) + (7*8*9*10) = 5167.

## Method 1 (Using Recursion) :

• Create a recursive function say term(int calculated, int current, int N)
• Declare a variable cur to hold the product of the terms and initialize it with 1.
• Base condition will be if(current == N+1) then, return 0. Here, current denotes the current term of the series.
• Now, run a loop to calculate the product of terms till current.
• Set i= calculate. Termination condition of the loop will be i>= calculated + current.
• Inside loop set cur *= i
• After execution of loop return cur + term(i, current+1, N)

## Code to Print F(N)th term in C++

Run
```#include<bits/stdc++.h>
using namespace std;

// Recursive function
int term(int calculated, int current, int N)
{
int i, cur = 1;

// Base Condition
if (current == N + 1)
return 0;

// product of terms till current
for (i = calculated; i < calculated + current; i++)
cur *= i;

return cur + term(i, current + 1, N);
}

// Driver Code
int main()
{
int N = 3;

cout<<term(1, 1, N);

return 0;
}```
`Output :127`

## Method 2 (Using Loop) :

• Create a function say term(int calculated, int current, int N) to calculate the required N-th term.
• Declare a variable result = 0.
• Run a while loop till current != N+1.
• Inside while loop declare a variable cur to hold the product of the terms and initialize it with 1.
• Now, run a loop to calculate the product of terms till current.
• Set i= calculate. Termination condition of the loop will be i>= calculated + current.
• Inside for loop set cur *= i.
• After execution of for loop set calculated = i, result += curr and increment current value by 1.
• After the execution of while loop return result.

## Code to Print F(N)th term in C++

Run
```#include<bits/stdc++.h>
using namespace std;

//Function to calculate N-th term
int term(int calculated, int current, int N)
{
int i, result = 0;

while(current != N + 1){

int cur = 1;
// product of terms till current
for (i = calculated; i < calculated + current; i++)
cur *= i;

calculated=i;
result += cur;
current++;
}

return result;
}

// Driver Code
int main()
{
int N = 3;

cout<<term(1, 1, N);

return 0;
}```
`Output :127`

### One comment on “Given an integer N the task is to print the F(N)th term in C++”

• amanbajpai5734

C++ Code :=>

#include
using namespace std;
int main()
{
int n,product,result=0;
cout<>n;
int k=1;
for(int i=1;i<=n;i++)
{
product=1;
for(int j=0;j<i;j++)
{
if(i==1)
product=1;
else{
product=product*k;
}
k++;
}
result=result+product;
}
cout<<result;
}