# Print Right Diamond Number Pattern Type7

2

33

444

5555

5555

444

33

2

## PREREQUISITE:

Basic knowledge of C language and use of loops.

## ALGORITHM:

1. Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
2. Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i
3. Use an if condition to to print the top half of the pyramid. if (i<=r/2) run a loop from j=0 to j<=i. The loop should be structured as for(j=0 ; j<=i ; j++)
4. Inside this loop print count.
5. Outside this loop increment count and print a newline
6. Else decrement count
7. Run a different loop from j=0 to j<r-i+1. The loop should be structured as for( j=0 ; j<r-i+1 ; j++).
8. Inside this loop print count.
9. After the loop print a newline.

## CODE IN C:

```#include
int main()
{
int i,j,r,count; //declaring integer variables i,j for loops , r for number of rows
printf("Enter the number of rows/columns :\n"); //asking user for the number of rows;
scanf("%d",&r); //taking number of rows and saving in variable r
count=2; //intialising count =3
for(i=1;i<=r;i++) //loop for number of rows
{
if(i<=r/2)
{
for(j=1;j<=i;j++) //loop to print digit in every column of a row
{
printf("%d",count); //printing digit
}
count++; //incrementing count
printf("\n"); //printing newline

}
else
{
count--;
for(j=0;j<r-i+1;j++)
{

printf("%d",count);
}

printf("\n");
}
}
}```

## DISPLAYING OUTPUT:

If you want to do the same code, but by using 2 inputs one for initializing the first term and then the number of times you want it to be printed.

Input:
3  4
Output:
3
44
555
6666
6666
555
44
3

`Program:#include<stdio.h>int main(){    int i,j,s,N,count=0;    scanf(“%d%d”,&s,&N);    for(i=s;count<4;count++)    {        for(j=0;j<count+1;j++)            printf(“%d”,i);        printf(“\n”);        i=i+1;    } for(i=s+N-2;count>0;count–)    {        for(j=0;j<count-1;j++)            printf(“%d”,i);        printf(“\n”);        i=i-1;    }    return 0;}`