# Increment Numbered Square Printing

1111

2222

3333

4444

## PREREQUISITE:

Basic knowledge of C language and loops.

## ALGORITHM:

1. Take number of rows/columns as input from the user and save it in any variable (‘r’in this case).
2. Run a loop ‘r’ number of times to iterate through the rows. From i=0 to i<r.  The loop should be structured as for( i=0 ; i<r ; i++).
3. Run a nested loop inside the previous loop to iterate through the columns. From  j=0 to j<r. The loop should be structured as for(j=0 ; j<r ; j++).
4. Inside the nested loop print ‘i’ to print the incremented value in each column of a row.
5. Inside the main loop print a newline to move to the next line after a row.

## CODE IN C:

```#include<stdio.h>
int main()
{
int i,j,r;                                       //declaring integer variables i,j for loops , r for number of rows
printf("Enter the number of rows/columns :\n");  //asking user for the number of rows;
scanf("%d",&r);                                  //taking number of rows and saving in variable r
for(i=1;i<=r;i++)                                //loop for number of rows
{
for(j=0;j<r;j++)                           //loop to print digit in every column of a row
{
printf("%d",i);                       //printing digit
}
printf("\n");                              //printing newline
}
}```

## TAKING INPUT:DISPLAYING OUTPUT:

### One comment on “Increment Numbered Square Printing”

• Vanshika

n=int(input())
for i in range(1,n+1):
for j in range(n+1):
print(i,end=””)
print(“\n”)