Access Array Using Pointer in C
Access Array Using Pointer:
On this page we will discuss about access array using pointer in C language and write a program for it.This will help to understand the basic structure of arrays and pointers.We can understand pointer as an variable which holds the address of another variable.
Access Array Using Pointer in C Language
- Array is collection of data items of homogeneous types at contiguous memory location.
- Pointer is itself a variable which holds the address of another variable.
- Array can be initialized at declaration where as pointer can’t be initialized at declaration.We can access the array elements using pointer.
- Pointer to array means the pinter variable will hold the address to the first element of array of base element of array let’s say p[0] where a is an array.
- If we use * before pointer variable it will return the value store at the address.
Example:
int p[5] = {8, 9, 10, 11, 12};
int *ptr = p 
Program 1:
#include <stdio.h>
int main ()
{
int p[5] = { 8, 9, 10, 11, 12 }, i;
int *ptr = p;
for (i = 0; i < 5; i++)
printf ("&p[%d] = %p \t p[%d] = %d\n", i, ptr + i, i, *(ptr + i));
return 0;
}
Output:
&p[0] = 0x7ffeafbc9190 p[0] = 8 &p[1] = 0x7ffeafbc9194 p[1] = 9 &p[2] = 0x7ffeafbc9198 p[2] = 10 &p[3] = 0x7ffeafbc919c p[3] = 11 &p[4] = 0x7ffeafbc91a0 p[4] = 12
Program 2:Modifying Elements of Array Using Pointer
Run
#include<stdio.h>
int main ()
{
int p[5] = { 8, 9, 10, 11, 12 }, i;
int *ptr = p;
*(ptr+3) = 16;
for (i = 0; i < 5; i++)
printf ("&p[%d] = %p \t p[%d] = %d\n", i, ptr + i, i, *(ptr + i));
return 0;
}
//4th element is modified from 11 to 16
Output:
&p[0] = 0x7ffef151f3c0 p[0] = 8 &p[1] = 0x7ffef151f3c4 p[1] = 9 &p[2] = 0x7ffef151f3c8 p[2] = 10 &p[3] = 0x7ffef151f3cc p[3] = 16 &p[4] = 0x7ffef151f3d0 p[4] = 12
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