## Armstrong Number

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.

```abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....
```

Example:

```Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9

Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723

Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634```

## C/C++

// C++ program to determine whether the number is
// Armstrong number or not
#include<bits/stdc++.h>
using namespace std;

/* Function to calculate x raised to the power y */
int power(int x, unsigned int y)
{
if( y == 0)
return 1;
if (y%2 == 0)
return power(x, y/2)*power(x, y/2);
return x*power(x, y/2)*power(x, y/2);
}

/* Function to calculate order of the number */
int order(int x)
{
int n = 0;
while (x)
{
n++;
x = x/10;
}
return n;
}

// Function to check whether the given number is
// Armstrong number or not
bool isArmstrong(int x)
{
// Calling order function
int n = order(x);
int temp = x, sum = 0;
while (temp)
{
int r = temp%10;
sum += power(r, n);
temp = temp/10;
}

// If satisfies Armstrong condition
return (sum == x);
}

// Driver Program
int main()
{
int x = 153;
cout << isArmstrong(x) << endl;
x = 1253;
cout << isArmstrong(x) << endl;
return 0;
}

### Java

// Java program to determine whether the number is
// Armstrong number or not
public class Armstrong
{
/* Function to calculate x raised to the
power y */
int power(int x, long y)
{
if( y == 0)
return 1;
if (y%2 == 0)
return power(x, y/2)*power(x, y/2);
return x*power(x, y/2)*power(x, y/2);
}

/* Function to calculate order of the number */
int order(int x)
{
int n = 0;
while (x != 0)
{
n++;
x = x/10;
}
return n;
}

// Function to check whether the given number is
// Armstrong number or not
boolean isArmstrong (int x)
{
// Calling order function
int n = order(x);
int temp=x, sum=0;
while (temp!=0)
{
int r = temp%10;
sum = sum + power(r,n);
temp = temp/10;
}

// If satisfies Armstrong condition
return (sum == x);
}

// Driver Program
public static void main(String[] args)
{
Armstrong ob = new Armstrong();
int x = 153;
System.out.println(ob.isArmstrong(x));
x = 1253;
System.out.println(ob.isArmstrong(x));
}
}

### Python

# Python program to determine whether the number is
# Armstrong number or not

# Function to calculate x raised to the power y
def power(x, y):
if y==0:
return 1
if y%2==0:
return power(x, y/2)*power(x, y/2)
return x*power(x, y/2)*power(x, y/2)

# Function to calculate order of the number
def order(x):

# variable to store of the number
n = 0
while (x!=0):
n = n+1
x = x/10
return n

# Function to check whether the given number is
# Armstrong number or not
def isArmstrong (x):
n = order(x)
temp = x
sum1 = 0
while (temp!=0):
r = temp%10
sum1 = sum1 + power(r, n)
temp = temp/10

# If condition satisfies
return (sum1 == x)

# Driver Program
x = 153
print(isArmstrong(x))
x = 1253
print(isArmstrong(x))