TCS NQT Averages Questions and Answers Quiz 1

Sum of observations of 1 to 15 = 15 x 15 = 225
Sum of observations of 1 to 8 = 8 x 20 = 160
Sum of observations of 8 to 15 = 8 x 18 = 144
Therefore, 8th observation
= Sum of observations of 1 to 8 + Sum of observations of 8 to 15 - Sum of observations of 1 to 15
= 160 + 144 - 225
= 304 - 225
= 79

The points scored by the team:-
Sum of the points of team = average score x number of players

= 49 x 11
= 539

The difference between scored points and to be scored points

= 46 -39 = 7

Therefore, The points scored by the team = 539 - 7 = 532.

Let the average after the 20th inning be P.
So, the average after the 19th inning will be (P-2)
Hence, 19(P-2) + 94 = 20P
=> P = 56

Total weight increased = (10 * 5.5) kg = 55 kgs
If x is the weight of new person , increase in weight = x - 55
Weight of new person, 55 = x -55
x = 110 kg

Required run rate =

\frac{ 312 - 2.45 *10} {40}
=\frac{ 312 - 24.5} {40}
= 7.18

Sum of weight of Vibudh, Srijan, Rajnish and Siddharth = 67 × 4 = 268 kg
Sum of weight of Vibudh, Rajnish, Siddharth and Tahir = 63 × 4 = 252 kg
Let, weight of Srijan = x kg
Then, weight of Tahir will be (x - 16) kg
Weight of Vibudh = (x - 16 - 18) = (x - 34) kg
So, x - 16 + x - 34 = 58 × 2
2x = 116 + 50
x = 83
Therefore, weight of Tahir = (83 - 16) = 67 kg
Reqd. average = \frac{83 + 67}{2} = 75 kg

Solution :

Let Jethalal's weight be "x" kg.

According to Jethalal, we have

59 < x <= 69

According to Jethalal's friend, we have

65 < x < 79

According to Champaklal, we have

x < 70

The values of 'x' which satisfy all the above inequalities are 59 and 79.

So, the different probable weights of Jethalal are 59 kg and 79 kg.

Average of 59 and 79 = (59 + 79) / 2

Average of 59 and 79 = 138 / 2

Average of 59 and 79 = 69

So, the average of different probable weights of Jethalal is 69 kg.

The average score of 11 IPL Matches is 99.

That is,

Sum of scores in 11 IPL Matches divided by 11 = 99

Multiply both sides by 9.

Sum of scores in 11 IPL Matches = 11 x 99

Sum of scores in 11 IPL Matches = 1089

Let "x" be his score in his next test.

Given : Average score of 12 IPL Matches is 103.

Then, we have,

(Sum of scores in 11 IPL Matches + x) / 12 = 103

\frac{(1089 + x) }{12} = 103

Multiply both sides by 12.

1089 + x = 103*12

1089 + x = 1236

Subtract 1089 from both sides.

x = 147

So, Kohli's score in the next test should be 147.

Number of days in last week = 7
Average of 7 days = 6.5
Sum of hours spent = Number of days in last week x Average of 7 days
= 7 x 6.5
= 45.5 hours

The average number of hours after removing 1 day = 5.5
Number of days left = 6

Sum of 6 days = 6 x 5.5
= 33 hours

Therefore, the hours of playing time did she have on the day which we removed
= 45.5 - 33 = 12.5 hours

Height of 3 boys Bikesh, Sam, and Suhas is
\frac{208}{3}\times 3 = 208 \text{ inches }
The height of Bikesh, Vishal, and Rakesh is
\frac{203}{3}\times 3 = 203 \text{ inches }.
With the help of this information, the height of 5 boys cannot be determined.