TCS NQT Allegations and Mixtures Questions Quiz 1

the concentration is given which is wrt 100, hence we can take x lt of 90% and (30-x)of 75%

x*90 + (30-x)*75 = 30*78

hence the ans is 6 liters.

a+b+c=48*3=144
a+b+c+d=47*4=188
b+c+d+e=48*4=192
d=188-144=44
e=3+44=47
b+c+d=192-47=145
a=188-145=43

total distance traveled by the car=40000km
so total distance traveled by 4 wheels=4*40000=160000
as all tires (4+1) are equally used
so average distance traveled by the each tyre=160000/5=32000

Let the actual amount of A be 4x and actual amount of B be 3x since A and B are in the ratio 4/3

amount of first basic element in the new alloy T (5/8)*4x + (1/3)*3x = (7x)/2

amount of second basic element in the new alloy T (3/8)*4x + (2/3)*3x= (7x)/2

so ratio of first basic element to second basic element: [(7x)/2 ] / [ 7x/2] = 1/1 = 1:1 ( Answer A)

Final quantity = initial quantity(1-(removed quantity/total)^no of times repeated

= 729(1-(n/729))⁶

Percentage of milk in first mixture

= [5/6] x 100 = 250/3 %

Percentage of milk in second mixture

= [7/9] x 100 = 700/9

Using Alligation method,



So, Required Ratio = [20/9] : [10/3] = 2:3

Let the quantity of mixture be X Liters

The cost of 1 L milk is = Rs 1.08 = 108 Paise

We have,

(X + 16) * 90 = (X * 108) + (16 * 0) (as cost of water is Zero)

90X + 16*90 = 108X

16 * 90 = 18X

X = (16 * 90)/18

X = 8 * 10

X = 80 L

Given 25 liters of sol has 20% sugar .
qty of sugar =(20%/100%)*25 =5 lit of sugar
(assume sugar qty in liter for easy calculation ).
therefore 25 lit sol contain 20 lit of water and 5 liter of sugar .
now the sol boils losing 10 liter of water .
therefore the new 15 liter sol contains 10 liter water and 5 liter sugar . there new % of sugar is 5/15 * 100 =33.33%

Consider 90 litre of solution1 and 60 litre of solution2

90 litre of solution1 contains 90*1/5=18 litre of milk and (90-18)=72 litre of water
60 litre of solution2 contains 60*1/3=20 litre of milk and (60-20)=40 litre of water

Mixture will have 18+20=38 litre of milk 72+40=112 litre of water
i.e., Quantity of milk : Quantity of water = 38 : 112 = 19 : 56

Take 75 litre of solution1. Quantity of milk = 75*1/5=15 litre. Profit earned in selling solution is 20%
assume cost price of 1 litre of milk = Rs.1
Cost price of 75 litre of solution1 = Rs.15.
Selling price of 75 litre of solution1 = 15*120/100 = Rs.18

Take 75 litre of mixture. Quantity of milk = 75*19/75=19 litre.
Cost price is Rs.19
Selling price will be same and is Rs.18
so there will be a loss
Loss = Rs.1 in selling 75 litre of the mixture
Percentage loss = 1*100/19 = 5.25% loss