Reverse an Array in Java
Reverse an Array in Java
Here, in this page we will discuss the program to reverse an array in java. We are given with an array and need to print that array in reverse order. Here we will discuss different approaches to reverse the given input array.
Here, in page we will discuss various method for reversing the array. Different methods are :
Method Discussed
- Method 1: Just print the array in reverse order
- Method 2: Actual in-place reversing of the original array
- Method 3: Recursive in-place reversing of the original array
Example :
- Input : arr[5] = [10, 20, 30, 40, 50]
- Output : Array after reversing, arr[5] = [50, 40, 30, 20, 10]
Method 1
- Run an iterative loop from the last index of the array
- Print each item one by one arr[i]
Method 1 : Java Code
Run
import java.util.Scanner;
public class Main
{
public static void main(String args[])
{
int arr[] = {10, 20, 30, 40, 50};
int n=arr.length;
for(int i=n-1; i>=0; i--)
System.out.print(arr[i]+" ");
}
}Output:
50 40 30 20 10
Method 2
- Take two variables start=0 and end=n-1
- Swap items at start & end indexes
- Do start++ & end–
- Stop when start & end indexes overlap one another
- Print the array
Time and Space Complexity :
- Time – Complexity : O(n)
- Space-Complexity : O(1)
Method 2 : Java Code
Run
import java.util.Scanner;
public class Main
{
public static void main(String args[])
{
int arr[] = {10, 20, 30, 40, 50};
int n=arr.length;
int start = 0, end = n-1;
while(start<end){
int temp = arr[start];
arr[start]=arr[end];
arr[end]=temp;
start++;
end--;
}
for(int i=0; i<n; i++)
System.out.print(arr[i]+" ");
}
}
output :
50 40 30 20 10
Method 3
Initially pass values of start = 0, end = n – 1
- Function gets called as reverseRecursive(arr, 0, len-1);
- In each recursive iteration swap arr[start] & arr[end]
- Make further recursive calls as reverseRecursive(arr, start + 1, end – 1);
- return when (start >= end)
- Print the array
Time and Space Complexity :
- Time – Complexity : O(n)
- Space-Complexity : O(n), require stack to store the recursive calls
Method 3 : Java Code
Run
import java.util.Scanner;
public class Main
{
static void reverseRecursive(int arr[], int start, int end)
{
if (start >= end)
return;
int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
// recursive call to swap arr[start+1] & arr[end-1]
reverseRecursive(arr, start + 1, end - 1);
}
public static void main(String args[])
{
int arr[] = {10, 20, 30, 40, 50};
int n=arr.length;
int start = 0, end = n-1;
reverseRecursive(arr, start, end);
for(int i=0; i<n; i++)
System.out.print(arr[i]+" ");
}
}Output :
50 40 30 20 10
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class HelloWorld {
public static void main(String[] args) {
int a[]={1,2,3,4,5};
int b[]=new int[a.length];
int j=0;
for(int i=a.length-1;i>=0;i–){
b[j]=a[i];
j++;
}
for(int i=0;i<a.length;i++){
System.out.println(b[i]);
}
}
}
import java.util.Scanner;
class Work {
void Disp() {
Scanner sc = new Scanner(System.in);
int n, sum = 0;
System.out.println(“Enter the Size :”);
n = sc.nextInt();
int a[] = new int[n];
System.out.println(“Enter the array elements:”);
for (int i = 0; i < n; i++) {
a[i] = sc.nextInt();
}
System.out.println("Array elements are:");
for (int i = 0; i = 0; i–) {
System.out.print(a[i] + ” “);
}
}
}
class RevArr {
public static void main(String args[]) {
Work w = new Work();
w.Disp();
}
}
import java.util.*;
public class Main{
public static void main(String[] args){
Scanner scn=new Scanner(System.in);
int n=scn.nextInt();
int[] arr=new int[n];
for(int i=0;i<n;i++){
arr[i]=scn.nextInt();
}
int i=0,j=arr.length-1;
while(i<=j){
int val=arr[i];
arr[i]=arr[j];
arr[j]=val;
i++;
j–;
}
for(int val:arr)
System.out.print(val+" ");
}
}