Deloitte Inverse Questions and Answers Quiz-1

Assume that in x days, one cow will eat one bag of husk.

1 x 7 x x = 7 x 1 x 7

The men already in Garrison = 500

Extra men = 300

Total men now ( 500 + 300 ) = 800 men

500 men provision 24 days

1 men provision 24 x 500 days

800 men provision = 24 x 500 / 800

= 15 days

Because, less number of basket balls -----> cost will be less
Given : 75 basketballs cost $1,143.75
Cost of one basket ball = 1143.75 / 75 = 15.25
Then, cost of 26 basket balls = 15.25 x 26 = 396.50
Hence, the cost of 26 basket balls is $ 396.50

Miguel raised $2,372.50 in 36.5 weeks

Amount raised in one week is

=  2372.5 / 36.5

=  $65

Amount raised in 20 weeks is

=  65 ⋅ 20

=  $1300

Hence, the money raised in 20 weeks is $1300

Lets assume x meters length wall will be made.

men wall days
---------------------
30(d) 56(d) 5(d)
40 x 3

(40/30 * 3/5) = x/56
=> x = (40/30 * 3/5 * 56)
=> x = 44.8 meters.

In a dairy farm 20 cows eat 20 bags of husk in 20 days. We have to calculate the days in which one cow eat one bag of husk.
Let number of days be 'x' .
Solution:
20 cows : 20 bags : 20 days = 1 cow : 1 bag : x days
20 : 20 : 20 = 1 : 1 : x
20 / 20 : 20 = 1 / 1 : x
1 : 20 = 1 : x
1 / 20 = 1 / x
x = 20
which shows that 1 cows will eat 1 bag of husk in 20 days.

 

In order to solve this sum we have to apply unitary method.

The formula is: [(no.of men)*(no.of days)*(no.of hours)]/(work).

Acc to the question, m1 = 4

w1 = 40.

d1 = 30.

m2 = 18.

d2 = 12.

w2 = ?

From the formula we can write, (4 * 30) / (40) = (18 * 12) / (w2)

or, w2 = (18 * 12 * 40) / (4 * 30)

or, w2 = 72.

Therefore, 18 men can reap 72 acres of land in 12 days. [Ans]

 

Answer sheets are work here. So
M1*D1*H1*W2 = M2*D2*H2*W1
9*12*5*2 = 4*30*H2*1
Solve, H2 = 9