Reverse a linked list without changing links between nodes (Data reverse only) in C++
Reverse a linked list without changing links between nodes (Data reverse only)
Here, in this page we will discuss Reverse a linked list without changing links between nodes in C++. We create a vector and store the elements of the linked list and them change the linked list node data by iterating the vector in reverse manner.
Algorithm :
- Create a node say current and set it to head.
- Now, Create a vector to store the node value in it. We will iterate over all nodes of linked list and push the current node data in vector and set current to next node. Repeat this till the current node does not become NULL.
- Now, again set current to head and take a variable say j and set it to vector.size()-1.
- Now, change the current node data with vector[j] and decrement the j and set current to next node. Repeat this till current node does not become NULL.
- In this way we can Reverse a linked list without changing links between nodes in C++
C++ program to reverse a linked list
Run
#include<bits/stdc++.h>
using namespace std;
/* Link list node */
struct Node
{
int data;
struct Node *next;
Node (int data)
{
this->data = data;
next = NULL;
}
};
struct LinkedList
{
Node *head;
LinkedList ()
{
head = NULL;
}
/* Function to reverse the linked list */
void reverse ()
{
Node *current = head;
std::vector < int >element;
while (current != NULL)
{
element.push_back (current->data);
current = current->next;
}
current = head;
int i = element.size () - 1;
while (current != NULL)
{
current->data = element[i--];
current = current->next;
}
}
/* Function to print linked list */
void display ()
{
struct Node *temp = head;
while (temp != NULL)
{
cout << temp->data << " ";
temp = temp->next;
}
}
void insert (int data)
{
Node *temp = new Node (data);
temp->next = head;
head = temp;
}
};
/* Driver code*/
int main ()
{
LinkedList ll;
ll.insert (10);
ll.insert (20);
ll.insert (30);
ll.insert (40);
cout << "Given linked list\n";
ll.display ();
ll.reverse ();
cout << "\nReversed Linked list \n";
ll.display ();
return 0;
}
Output :
Given linked list 40 30 20 10 Reversed Linked list 10 20 30 40
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