Insertion at End in Singly Linked List in C++
How to insert an element at End in Singly Linked List in C++?
Insertion at End in Singly Linked List in C++ – In this post we will understand how to insert a new node at the end of the singly linked list in C++. Lets go and code Program Insert node at end of linked list in C++. Linked list in C++ is part of a linked list and is a type of linear data structure. Linked list is made up of two parts node and pointer where node contains the data and pointer contains the address of the next node.
This is one of the most commonly used operations while working with linked lists. Whether you’re building a list from scratch or adding new elements, knowing how to insert at the end is essential.
Singly Linked List definition in C++
Nodes of singly linked list is created by using the code mentioned besides.
This set of code will construct linked list by creating each node of the list.
class Node
{
int data;
Node *next;
}; 
C++ program to insert an element at end of singly linked list
This method uses non member functions and head is passed within function signatures.
#include<iostream>
using namespace std;
class Node
{
public:
int data;
Node *next;
};
void insertEnd(Node** head, int data)
{
Node* freshNode = new Node();
freshNode->data = data;
// since this will be the last node so it will point to NULL
freshNode->next = NULL;
//need this if there is no node present in linked list at all
if(*head==NULL)
{
*head = freshNode;
cout << freshNode->data << " inserted" << endl; return; } struct Node* temp = *head; // traverse to the last node of Linked List while(temp->next!=NULL)
temp = temp->next;
// assign last node's next to this freshNode
temp->next = freshNode;
cout << freshNode->data << " inserted" << endl;
}
void display(Node* node)
{
//as linked list will end when Node is Null
while(node!=NULL)
{
cout << node->data << " "; node = node->next;
}
cout << endl;
}
int main()
{
Node* head = NULL;
insertEnd(&head,7);
insertEnd(&head,8);
insertEnd(&head,9);
insertEnd(&head,10);
display(head);
return 0;
}Output
7 inserted 8 inserted 9 inserted 10 inserted 7 8 9 10
This method uses member functions and head the data member of class so it need not be passed with functions signatures.
#include<iostream>
using namespace std;
class Node
{
public:
int data;
Node *next;
};
class LinkedList
{
private:
Node* head;
public:
LinkedList()
{ // constructor
head = NULL;
}
int calcSize();
void insertLast(int data);
void display();
};
void LinkedList::insertLast(int data)
{
Node* freshNode = new Node();
freshNode->data = data;
// since this will be the last node so it will point to NULL
freshNode->next = NULL;
//need this if there is no node present in linked list at all
if(head==NULL)
{
head = freshNode;
cout << freshNode->data << " inserted" << endl; return; } struct Node* temp = head; // traverse to the last node of Linked List while(temp->next!=NULL)
temp = temp->next;
// assign last node's next to this freshNode
temp->next = freshNode;
cout << freshNode->data << " inserted" << endl;
}
void LinkedList::display()
{
Node* node = new Node();
node = head;
//as linked list will end when Node is Null
while(node!=NULL)
{
cout << node->data << " "; node = node->next;
}
cout << endl; } int main() { LinkedList* mylist = new LinkedList(); mylist->insertLast(7);
mylist->insertLast(8);
mylist->insertLast(9);
mylist->insertLast(10);
mylist->display();
return 0;
}Output
7 inserted 8 inserted 9 inserted 10 inserted 7 8 9 10
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FAQs - Insertion at End in Singly Linked Lists in C++
It means adding a new node as the last node of the linked list. This new node’s next pointer will point to NULL, making it the new tail of the list.
The time complexity is O(n) because we need to traverse the entire list to reach the last node, unless we maintain a tail pointer.
Yes, if we maintain a tail pointer (a reference to the last node), we can insert in O(1) time without traversing the list.
If the list is empty, the new node becomes both the head and tail of the list, as it’s the only node present.
In a singly linked list, NULL indicates the end of the list. It tells us that there is no node after the current one.
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