TCS NQT Input/Output Quiz- 3

In the given code, i=5, j=6 and k=0

Since in function f address of i and j are passed as an argument,

*p = &i and *m=&j

*m = *m+3 => *m = (3+3) =>*m =  9   // as, *m = j so j also becomes 9 i.e, j=9

 *p=*p+*m => *p =(5+9) => *p = 14 // as, *p = i so i will also change to 14

 k=i*j  => k=(14*9) => 126.

Hence, we get the output as 126.

 

 In the given code :

num is set to 4:

Now, the outer for loop will execute, as the condition i>0 i.e, 4>0 //True

The inner for loop will execute 3 times, and print * on the screen,

After that num will decrement by 1 and become 3 and the cursor moves to the next line.

Again, the outer for loop will execute, as the condition i>0 i.e, 3>0 //True

The inner for loop will execute 2 times, and print * on the screen,

After that num will decrement by 1 and become 2 and the cursor moves to the next line.

Again, the outer for loop will execute, as the condition i>0 i.e, 2>0 //True

The inner for loop will execute 1 times, and print * on the screen,

After that num will decrement by 1 and become 1 and the cursor moves to the next line.

Again, the outer for loop will execute, as the condition i>0 i.e, 1>0 //True

The inner for loop will execute 0 times, and will not print * on the screen,

After that num will decrement by 1 and become 0 and the cursor moves to the next line.

Now, the condition of the outer loop will become false. And get terminated.

 

Explanation : i = 16, i<<1 => i*(2^1) => 16*2 =>32
i>>2 => i/(2^2) = 16/4 => 4
So the output will be 324.

n function foo(10) , 10 is passed as parameter,

So, i=10, j=5 

j=j/i => j=5/10 => j=0.5

%0.3f will print the floating number upto 3 decimal points, so 0.500will printed, and function will terminated and return 0.500000

x=0.500000

%0.2f will print x upto 2 decimal points so, 0.50 gets printed

Hence, the output will be : 0.5000.50

a=4, b=2

Exp=(a+b)/b => (4+2)/2 => 3

Exp2=a+b/b => 4 + (2/2) => 5   //precedence of the / operator is greater than + operator.

Exp3=a+(b/b) => 4 + (2/2) => 5

Hence, the output will be 3 5 5

coins=15, split = 3
--coins (decrements the value of coins by 1) // coins=14
Rest =coins%split => rest = 14%3 => 2

Explanation : Since i=3

And the case with expression 8%5 will result in 3 so, dates will get printed on the output screen.

Explanation : Initially, a=5

res = a++  // first res is assigned with a i.e, 5 then a is incremented by 1, so, res=5, a=6

res1 = ++a // first a is incremented by 1,then res1 is assigned with a i.e, 7 then so, res1=7, a=7

res--  // decremented res by 1 so, res=4

--res1 //decremented res1 by 1 so, res1 = 6

res-=res1 => res = res-res1 => res = 4-6 => res=-2

Explanation : Initially toys=0 (as toys is not assigned so, it takes 0 by default)

As, no condition is provided in for loop so, 0 will be printed and then

Condition of if(toys++ == 4) is checked 0 != 4 //so if condition is false, but it increments the toys by 1 so toys = 1

Increment condition of for loop increments the toys by 1 again, so toys = 2

 

Again for loop will execute so, 2 (i.e, toys value) will be printed and then

Condition of if(toys++ == 4) is checked 2 != 4 //so if condition is false, but it increments the toys by 1 so toys = 3

Increment condition of for loop increments the toys by 1 again, so toys = 4

 

Again for loop will execute so, 4 (i.e, toys value) will be printed and then

Condition of if(toys++ == 4) is checked 4 == 4 //so if condition is true, so loop gets terminated due to break statement

 

Hence, the output will be 024

Explanation : 

Initially a=0

Now inside the if condition post increment operator is used so it first checks the condition then increments the value of a so if condition (a++) leads to false as a=0.

Since, if will not executed so else block get executed and we get NO as output.