Accenture Time speed and Distance Quiz-1

First train start in 10 am and 2nd train start train 10:30
So the 1st train cover 30 km distance in 10:30.
Now, both train time are equal
Let the train distance = x
time 1= time 2
x-30/60=x/75
So x=150 km

Correct Answer : C

Explanation:

With 60 kmph in 3 hours train ‘A’ covers 180 kms.
Train B speed is 12kmph more than train ‘A’. Because train B started 3 hours later so it has to cover 180 extra with extra 12kmph speed. Time taken is = 180/12 = 15 hours So 15 hours from 2p.m is 5a.m on the next day

Let the actual distance travelled be x km.

Then, \frac{x}{10}=\frac{x +20}{14}

14x = 10x + 200

4x = 200

x = 50 km

Let the speed of two trains be 7x and 8x km/hr.

Then, 8x =\frac{(400)}{(4)}= 100
x = \frac{100}{8}

Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.

Let length of platform = P m
we know,
distance = speed × time
here,
time = 1.5 × 60 sec = 90 sec
speed = 54 × 5/18 = 15 m/s
distance = (1200 + P) m

1200 + P = 15 × 90
1200 + P = 1350
P = 150 m

hence, Length of platform = 150 m

Length of the Train = 240 m.
Time taken by it to cross the Pole = 15 seconds.
∵ Speed = Distance or length of the train/Time
∴ Speed = 240/15
⇒ Speed of the train = 16 m/s
= 16×3.6 km/h
= 57.6 km/h
The speed of the train is 57.6 km/h

Let length of train is L

speed of train = 60kmph = 60 × 5/18 = 50/3 m/s

speed of man = 45kmph = 45 × 5/18 = 25/2 m/s

a/c to question, both train and man are going same direction.

so, relative speed of train with Respect to man = 50/3 m/s - 25/2 m/s

= (25/6) m/s

train crosses man in 48 second

so, length of train = relative speed of train with respect to man × time taken

= 25/6 × 48 = 25 × 8 = 200m

hence, length of train is 200m

As a work is done by 28 men in 15 days at the rate of 6hr per day
or, 28 men take 15×6 hr to finish the work.
or, 28 men take 90 hr to finish the work .
or, 1 men will take 90×28 hr to finish 1 work.
or, amount of work done by 1 men in 1 hr = 1/2520 work

no. of days =2520/21×8=2520/168= 15 days.

A's Speed:B's Speed=rootof(b):rootof(a)
=>8:x=rootof(10/3):rootof(16/3)
On solving we get,
x={2 \times rootof(10)}
x={2 \times 3.6}
x=6.32 kmph.

28 children can do a piece of work in 50 days

⇒ 50 days = 28 children

The number of days is inversely proportional to the number of children.

⇒ The more days we have, the fewer children we need

Find number of children needed to complete the work in 1 day:

50 days = 28 children

1 day = 28 x 50 = 1400 children

Find number of children needed to complete the work in 30 day:
1 day = 1400 children

30 days = 1400 ÷ 30 = 46.67 ≈ 47 complete days