TCS Coding Questions 2022 Day 2 Slot 1

29 comments on “TCS Coding Questions 2022 Day 2 Slot 1”

• 
  

  Bharti

  Using Python

  n=int(input())
  e=[]
  l=[]
  max=0
  sum=0
  for i in range(0,n):
  el=int(input())
  e.append(el)

  for i in range(0,n):
  li=int(input())
  l.append(li)

  for i in range(n-1):
  sum+=e[i]-l[i]
  if sum>max:
  max=sum
  a=sum
  print(a)

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• 
  

  Dpa

  #Using python
  n=int(input())
  e=[int(input()) for i in range(0,n)]
  l=[int(input()) for i in range(0,n)]

  m,c=0,e[0]-l[0]
  for i in range (1,n):
  c=c+e[i]-l[i]
  if(c>m):
  m=c

  print(m)

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• 
  

  akshaychaudhari8668

  #Code in CPP
  int main()
  {
  int T=5;
  int E[5]={7,0,5,1,3};
  int L[5]={1,2,1,3,4};
  int m=0,sum=0;
  for(int i=0;i<T ;i++)
  {
  sum = sum + (E[i]-L[i]);
  m = max(sum,m);
  }
  cout<<m;
  return 0;
  }

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• 
  

  siddharthabhunia2020

  #include
  using namespace std;

  int main()
  {
  int t, mg = INT_MIN, gn = 0, time_interval = 0; // mg-Max Gusest AND gn-Gues_Now
  int entry[100];
  int exit[100];

  cin >> t;

  for (int i = 0; i > entry[i];
  }
  for (int i = 0; i > exit[i];
  }

  for (int i = 0; i < t; i++)
  {
  if ((gn + entry[i]) < exit[i])
  {
  cout << "Invalid Input" << endl;
  time_interval = 0;
  mg = 0;
  break;
  }
  gn = gn + entry[i] – exit[i];

  if (mg 0)
  {

  cout << "Maximum number of guests on cruise at an instance: " << mg << " Time Interval No:" << time_interval;
  }

  return 0;
  }

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• 
  

  Anup

  //Python
  x = int(input())
  e = list(map(int,input().split(“,”)))
  l = list(map(int,input().split(“,”)))
  a = []
  c = 0
  for i in range(x):
  c = c +e[i]-l[i]
  a.append(c)
  print(max(a))

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• 
  

  Suresh

  E=[]
  L=[]
  T = int(input())
  for i in range(T):
  e=int(input())
  E.append(e)
  for i in range(T):
  l=int(input())
  L.append(l)
  Sum=0
  Max=0
  for i in range(T):
  Sum+=E[i]-L[i]
  Max=max(Sum,Max)
  print(“output”, Max)

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• 
  

  nuthalapatidinesh098

  E=[]
  L=[]
  T=int(input(“range T:”))
  for i in range(T):
      e=int(input(“E:”))
      E.append(e)
  for i in range(T):
      l=int(input(“L:”))
      L.append(l)
  Sum=0
  Max=0
  for i in range(T):
      Sum+=E[i]-L[i]
      Max=max(Sum,Max)
  print(“output”,Max)

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• 
  

  Ankan

  //Using C
  #include
  int main()
  {
  int t,i,total=0,count=0;
  printf(“Enter no. of hours:”);
  scanf(“%d”,&t);

  int a[t],b[t];

  printf(“\nEnter the val of a array:”);
  for(i=0;i<t;i++)
  {
  scanf("%d",&a[i]);
  }

  printf("\nEnter the val of b array:");
  for(i=0;i<t;i++)
  {
  scanf("%d",&b[i]);
  }

  for(i=0;i<t;i++)
  {
  total += a[i]-b[i];
  if(totalcount)
  {
  count=total;
  }
  }

  printf(“%d”,count);
  return 0;
  }

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• 
  

  072

  Using Python
  time=int(input())
  entry=[int(x) for x in input().split()]
  exit=[int(x) for x in input().split()]
  count=0
  guests=[]
  for i in range(len(entry)):
  count=count+entry[i]-exit[i]
  guests.append(count)
  print(max(guests))

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• 
  

  RATUL

  java code
  ———————————————————————————————————————————————————————————————————————————————————————- public static void main(String[] args) {
  // TODO code application logic here
  int t = 0;
  Scanner sc = new Scanner(System.in);
  t=sc.nextInt();
  int e[]=new int[t];
  int l[]=new int [t];
  for(int i=0;i<t;i++)
  {
  e[i]=sc.nextInt();
  }
  for(int i=0;i<t;i++)
  {
  l[i]=sc.nextInt();
  }
  int v[]=new int[t];
  v[0]=e[0]-l[0];
  for(int i=1;i<t;i++)
  {
  v[i]=v[i-1]+e[i]-l[i];
  }

  int m=v[0];
  for(int i=0;i<t;i++)
  {
  if(m<v[i])
  m=v[i];
  }

  System.out.println(m);
  }

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• 
  

  suraj

  using python

  n = int(input(“Enter number of elements : “))

  a = list(map(int,input(“\nEnter the numbers : “).strip().split()))[:n]
  b = list(map(int,input(“\nEnter the numbers : “).strip().split()))[:n]
  temp=[]
  for i in range (0,n):
  s=a[i]+b[i]
  temp.append(s)
  print(max(temp))

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• 
  

  Ansh

  C CODE FOR THIS QUESTION

  #include
  #include
  void main()
  {
  int max = INT_MIN;
  int sum = 0;
  int t =4;
  int E[5] = {3,5,2,0};
  int n = sizeof(E)/sizeof(E[0]);
  int L[5] = {0,2,4,4};
  int m = sizeof(L)/sizeof(L[0]);
  int j =0,k=0;
  for(int i=0;i<t;i++)
  {
  while(j<n && kmax)
  {
  max = sum;
  }
  }
  }

  printf(“%d”,max);
  }

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• 
  

  Ansh

  **while(j<n && k<m)
  {
  max = sum;
  }
  }
  } printf(“%d”,max);
  }

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• 
  

  goutham

  T=int(input(“value of number T: “))
  E=0
  L=0
  N=0
  Mox=0
  for i in range(1,T+1):
  E=int(input(“value of entry: “))
  L=int(input(“value of exit: “))
  N=N+E-L
  Mox=max(N,Mox)
  print(“maximum”,Mox)
  print(“Hour”,i,”:”)
  print(“Entry:”,E,” “,”Exit:”,L)
  print(“No. of guests on ship:”,N)
  print(“Hence,the maximum number of guests within {0} hours is {1}”.format(T+1,Mox))

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• 
  

  Tamradhwaj

  java
  import java.util.Scanner;

  class GFG {
  public static void main(String[] arg) {
  Scanner sc = new Scanner(System.in);
  int a = sc.nextInt();
  int e = 0;
  int y[] = new int[a];
  int z[] = new int[a];
  for (int i = 0; i < a; i++) {
  y[i] = sc.nextInt();
  }
  for (int i = 0; i < a; i++)
  z[i] = sc.nextInt();

  for (int j = 0; j <= 0; j++) {
  e = y[j] – z[j];
  }
  for (int j = 1; j < a; j++) {
  e = e + y[j] – z[j];
  }
  System.out.println(e);
  }
  }

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