DXC Technology Equations Questions and Answers Quiz-1

Let, x be the member in the family excluding father.

so, 1/4 = 3(3/4x) [as, 3/4th part of cake is equally distributed among x people]

Now, 1/4 = 9/4x

=> x = 9

So, total member in the family =x+father = 9+1 = 10

Let income of A and B be 3x and 2x respectively. Also, their expenditure is 5y
and 3y.
Now, according to question,
3x-5y = 1000 ------- (i)*3
2x-3y = 1000 ---------- (ii)*5
9x-15y-10x+15y = 3000-5000;
Or, -x = -2000;
Or, x = 2000;
Then, income of A = 3x = 3*2000 = Rs. 6000.
income of A = 2x = 2*2000 = Rs. 4000.

let fix unit be x and cost of each unit be y
650y + x =2130 (1)
720y + x = 2340 (2)
solving both the equation we will have y=3
now placing y value in any of the equation give x=180(fixed value)
so now we will have 180 +(940*3)=3000
The correct answer is: Rs. 3,000

(m⁴ +m^-4 ) = 47

=>(m² +m^-2 )²  - 2 = 47

=>(m² +m^-2 )² = 47+2

=>(m² +m^-2 ) = 7  or (m² +m^-2 ) = -7

If, (m² +m^-2 ) = -7

=> (m +m^-1 )²  - 2 = -7

=>(m +m^-1 )²   = -5 [ Not possible]

Now,

(m² +m^-2 ) = 7

=>(m +m^-1 )²  - 2 = 7

=> (m +m^-1 )²  = 9

=>(m +m^-1 ) = 3 or -3

Putting the values K = 12, L = -2. M = 6

2x+y+z = 12......................(i)

x-3y+z=-2..........................(ii)

4x+y-z = 6..........................(iii)

Solving these equations, we get x = 2, y=3, z=5

Now, x^2 = 2^2 = 4

 

[f(a, b) + g(a, b)]=(a³ + b³ ) - (a/b) + (a/b) = (a³ + b³ )

At, a=2,b=-1 we get;

(a³ + b³ ) = 8 -1 = 7

Let the costs of each kg of apples and each kg of rice be Rs.a and Rs.r respectively.
10a = 24r and 6 * 20.50 = 2r
a = 12/5 r and r = 61.5
a = 147.6
Required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5
= 590.4 + 184.5 + 102.5 = Rs.877.40

Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r)
=> 2p = q + r

Adding 'p' both sides,
3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r)
=> 3q = p + r

Adding 'q' both sides,
4q = p + q + r = 1200
=> q = Rs.300
r = 1200 - (p + q)
=> r = Rs.500.

If Vijay gives 'x' marbles to Ajay then Vijay and Ajay would have V - x and A + x marbles.
V - x = A + x --- (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A - 2x and V + 2x marbles.

V + 2x - (A - 2x) = 30
=> V - A + 4x = 30 --- (2)
From (1) we have V - A = 2x
Substituting V - A = 2x in (2)
6x = 30 => x = 5.

Total distance traveled = 1800 km.
Distance traveled by plane = 600 km.
Distance traveled by bus = x
Distance traveled by train = 3x/5
=> x + 3x/5 + 600 = 1800
=> 8x/5 = 1200
=> x = 750 km.