Accenture Flowcharts Visual Reasoning DI Quiz-1

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For the value of N equal to 0, the flowchart gets stuck in an infinite loop.

approved_amt = sal * 3 * (60 - age)
approved_amt = 60,000 * 3 * (60 - 28)

approved amt = 57,60,000 Rs. So, yes, he would get a loan equal to Rs. 57,60,000.

ShortCut By :: Laboni

approved_amt=60000*3*(60-28)=Rs. 5,760,000

approved_amt = sal * 5 * (60 - age) = 15,000 * 5 * (60 - 35) = 18,75,000 Rs.

Given Box 4 = A
Also, (1) means number in Box 1;
For A,
IS (3) > (1) ? NO --(1)
IS (2) > (1) ? NO --(2)
IS (3) > (2) ? NO --(3)
ANSWER
The largest number is in BOX 1,
Because number in BOX 1 is not smaller than number in Box 2 and 3(refer (1) and (2)),
And, The smallest number is in BOX 3,
Because number in BOX 3 is not greater than number in Box 1 and Box 2(refer (1) and (3)).

Assume Box 2 has number 2, Box 3 has number 3 and so on.
And Box 1 has number 10
Instruction 1 : 2 [Box 2] + 2[Box 2] = 4[Box 2]
Instruction 2 : 2 [Box No.] + 2 = 4 [Box No.]
Instruction 3 : IS 10 [Box 1] < 4 [Box No.] ? NO
Instruction 1 : 4 [Box 4] + 4{Box 4] = 8[Box 4]
Instruction 2 : 4 [Box No.] + 2 = 6 [Box No.]
Instruction 3 : IS 10 [Box 1] < 6 [Box No.] ? NO
Instruction 1 : 6 [Box 6] + 6 [Box 2] = 12[Box 6]
Instruction 2 : 6 [Box No.] + 2 = 8 [Box No.]
Instruction 3 : IS 10 [Box 1] < 8 [Box No.] ? NO
Instruction 1 : 8 [Box 8] + 8 [Box 8] = 16[Box 8]
Instruction 2 : 8 [Box No.] + 2 = 10 [Box No.]
Instruction 3 : IS 10 [Box 1] < 10 [Box No.] ? NO
Instruction 1 : 10 [Box 10] + 10 [Box 10] = 20[Box 10]
Instruction 2 : 10 [Box No.] + 2 = 12 [Box No.]
Instruction 3 : IS 10 [Box 1] < 12 [Box No.] ? YES
ANSWER is 10

Instruction 1 : 5 [Box 4] + 2 [Box 10] = 3 [Box 1]
Instruction 2 : 3 [Box 1] + 3 [Box 6] = 6 [Box 1]
Instruction 3 : IS 6 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 6 [Box No.] + 3[Box 6] = 9 [Box No.]
Instruction 5 : IS 13 [Box 2] > 9[Box No.] ? = YES
Instruction 6 : 7[Box 9] - 1 = 6 [Box 9]
Instruction 2 : 6 [Box 1] + 6 [Box 9] = 12 [Box 1]
Instruction 3 : IS 12 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 9[Box No.] + 3[Box 6] = 12[Box No.]
Instruction 5 : IS 13 [Box 2] > 12 [Box No.] ? = YES
Instruction 6 : 6 [Box 9] -1 = 5 [Box 9]
Instruction 2 : 12 [Box 1] + 2 {Box 12] =14[Box 1]
Instruction 3 : IS 14 [Box 1] evenly divisible by 4? = NO
Instruction 4 : 12 [Box No.] + 3 [Box 6] = 15 [Box No.]
Instruction 5 : IS 13 [Box 2] > 15 [Box No.] ? = NO
ANSWER Box 1 = 14

Instruction 1 : 0 [Box 3] + 1 [Box 11] = 1 [Box 11]
Instruction 2 : 1 [Box 1] + 1 [Box 11] = 2 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 2 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 2 [Box 5] + 2 [Box 2] = 4 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 [Box 4]
Instruction 4 : IS 4 [Box 5] = 6 [Box 10] ? NO
Instruction 5 : 9 [Box 4] - 6 = 3 [Box 4]
Instruction 6 : 4 [Box 5] + 2 [Box 2] = 6 [Box 5]
Instruction 3 : 3 [Box 4] * 3 [Box 4] = 9 {box 4]
Instruction 4 : IS 6 [Box 5] = 6 [Box 10] ? YES
Instruction 7 : 24 [Box 7] - 6 [Box 5] = 18 [Box 8]
Instruction 8 : 9 [Box 4] + 18 [Box 8] = 27 [Box 6]
ANSWER Box 6 = 27

None of the available answers is the correct:

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step 1  : ins 1  : 2[Box 11] 3 = 5[Box 11]

step 2  : ins 2  : 8[Box 1] -> 8[Box 10]

step 3  : ins 3  : is 1 an odd number? YES

step 4  : ins 4  : go to instruction 6[Box 2[Box 6]]

step 5  : ins 6  : 4[Box 5] 5[Box 11] = 9[Box 11]

step 6  : ins 7  : change ins2: [Box 1 1] -> [Box 10 - 1]

step 7  : ins 8  : 9 < 8[Box 1] ? NO

step 8  : ins 9  : go to instruction 2

step 9  : ins 2  : 6[Box 2] -> 6[Box 9]

step 10 : ins 3  : is 2 an odd number? NO

step 11 : ins 6  : 4[Box 5] 9[Box 11] = 13[Box 11]

step 12 : ins 7  : change ins2: [Box 2 1] -> [Box 9 - 1]

step 13 : ins 8  : 8 < 8[Box 1] ? NO

step 14 : ins 9  : go to instruction 2

step 15 : ins 2  : 5[Box 3] -> 5[Box 8]

step 16 : ins 3  : is 3 an odd number? YES

step 17 : ins 4  : go to instruction 6[Box 2[Box 6]]

step 18 : ins 6  : 4[Box 5] 13[Box 11] = 17[Box 11]

step 19 : ins 7  : change ins2: [Box 3 1] -> [Box 8 - 1]

step 20 : ins 8  : 7 < 8[Box 1] ? YES

ANSWER: 5[Box 8] and 17[Box 11]

FALSE

Explanation.

even if Box 3 is updated instead of Box 2 in instruction C,

In instruction D, Number in Box 2 is compared with Box 7, and the value is anyway greater, so the result is YES there and thus exiting and finishing the loop.