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Quiz 1

Question 1

Time: 00:00:00

A man sold two houses for Rs. 7.8 lakhs each. On the one, he gained 5% and on the other, he lost 5%. What percent is the effect of the sale on the whole?

0.25 % loss

0.25 % gain

25% loss

25% gain

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Loss% formula = a^2/100 %

Loss% = (5^2/100) = ¼% = 0.25%

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Question 2

Time: 00:00:00

A horse and a cow were sold for Rs. 12000 each. The horse was sold at a loss of 20 % and the cow at a gain of 20 %. The entire transaction resulted in

No loss or gain

Loss of Rs. 1000

Gain of Rs. 1000

Gain of Rs. 2000

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Loss% = (20/10)^2 = (2)^2 = 4%

Total S.P = Rs. 24000

Total C.P = Rs. (100/96 × 24000) = Rs. 25000
Calculating the loss:
Loss
=
Total C.P
−
Total S.P
=
25000
−
24000
=
1000
Loss=Total C.P−Total S.P

Loss = 25000-24000 = Rs. 1000

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Question 3

Time: 00:00:00

A merchant sold his goods for Rs. 75 at a profit percent equal to C.P. The C.P was:

Rs. 40

Rs. 50

Rs. 60

Rs. 70

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Let C.P = Rs. X

X + X% of X = 75

X^2 + 100 X – 7500 = 0 Or (X+ 150) (X - 50) = 0

X = 50 (neglecting X= - 150)

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Question 4

Time: 00:00:00

Profit after selling a commodity for Rs. 425 is same as loss after selling it for Rs.355. The cost of the commodity is:

Rs. 385

Rs. 390

Rs. 395

Rs. 400

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: C.P = Rs. X

425 – X = X – 355 (or )

2X = 780 or X= 390

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Question 5

Time: 00:00:00

If two mixers and one T.V cost Rs. 7000. While two T.V s and one mixer cost Rs. 9800. The value of one T.V is:

Rs. 2800

Rs. 2100

Rs. 4200

Rs. 8400

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2X + Y = 7000

X + 2Y = 9800

Solving (i) and (ii), we get Y = 4200

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Question 6

Time: 00:00:00

Bhajan Singh purchased 120 reams of paper at Rs. 80 per ream. He spent Rs. 280 on transportation. Paid octrai at the rate of 40 paise per ream and paid Rs. 72 to the coolie. If he wants to have a gain of 8 %. What must be the selling price per ream?

Rs. 86

Rs. 87.48

Rs. 89

Rs. 90

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C.P of 120 reams = Rs. (120 × 80 + 280 + 72 + 120 × 40) = Rs. 10000

C.P of 1 ream = (10000/120) = Rs. (250/3)

S.P of 1 ream = Rs. (108/100 × 250/3) = Rs. 90

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Question 7

Time: 00:00:00

A man sells a car to his friend at 10 % loss. If the friend sells it for Rs. 54000 and gains 20 %. The original C.P of the car was:

Rs. 25000

Rs. 37500

Rs. 50000

Rs. 60000

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S.P = Rs. 54000,

Gain earned = 20%

C.P = Rs. (100/120 × 54000) = Rs. 45000

S.P = Rs. 45000 and loss = 10%

C.P = Rs. (100/90 × 45000) = Rs. 50000

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Question 8

Time: 00:00:00

A person bought an article and sold it at a loss of 10 % if he had bought it for 20 % less and sold it for Rs. 55 more he would have had a profit of 40 %. The C.P of the article is:

Rs. 200

Rs. 225

Rs. 250

None of these

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C.P = Rs. X

S.P = Rs. (90/100 × X) = Rs. (9/10 X)

C.P = Rs. (80/100 × X) = Rs. (4X/5) Gain = 40%

New S.P = Rs. (140/100 × 4X/5)

= Rs. (28/25 X) 28/25 X – 9/10 X = 55 or X = 250

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Question 9

Time: 00:00:00

At what price must kantilal sell a mixture of 80 kg sugar at Rs. 6.75 per kg with 120 kg at Rs. 8 per kg to gain 20%?

Rs. 7.50 per kg

Rs. 8.20 per kg

Rs. 8.85 per kg

Rs. 9 per kg

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C.P of 200 kg of sugar = Rs. (80 × 6.75 + 120 × 8) = Rs. 1500

C.P of 1 kg = Rs. (1500/200) = Rs. 7.50

Gain required = 20%

S.P of 1 kg = (120% of Rs. 7.50)

= Rs. (120/100 × 7.50) = Rs. 9 per kg

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Question 10

Time: 00:00:00

Subhash purchased a tape recorder at 9/10th of its selling price and sold it at 8% more than its S.P. His gain is:

10%

%18

20%

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S.P be Rs. X C.P paid by Subhash = Rs. 9X/10

S.P received by Subhash = Rs. (108% of Rs. X)

= Rs. 27X/25

Gain = Rs. (27X/25 – 9X/10)

= Rs. 9X/50 Gain = (9X/50 × 10/9X × 100)% = 20%

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["0","40","60","80","100"]

["Need more practice! \r\n","Keep trying! \r\n","Not bad! \r\n","Good work! \r\n","Perfect! \r\n"]

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