TCS Problems On Ages Quiz-1

At present

Age of Umesh = x

Age of Reena is Y age of Mahesh is m

after 6 years

X+6=4(y+6)

X+6=4y+24

But it is given that age of Mahesh is equal to 7 times age of Reena

So

7y+6=4y+24

3y+6=24

3y=18

Y=6

Age of Mahesh is equal to 7 times the age of Reena

X=7 x 6

=42

Video solution:

Total Age of 10 students and Teacher = 11 x 15 = 165

Total age of first 7 students = 7 x 15 = 105

Total age of 3 students = 3 x 11 = 33

Thus total age of students = 33 + 105 = 138

Age of Teacher = 165 - 138 = 27

Since its 13 years ago

Nina's 13 year ago age = Present age - 13 = 37 - 13 = 24

Aman's 13 year ago age = Present age - 13 = 59 - 13 = 46

Ratio = \frac{24}{46} = 12:23

Video solution:

Explanation:

4 year back,

The average age of the family = 19 years

Sum or Total of all ages of all 4 family members = 19 x 4 =76 years

 

In the present day, that means after 4 years,

Sum or Total of present ages of these 4 family members = 76+(4x4) =92 years

 

Let the child’s present ages be K years.

Now the family is of 5 members(because a child has been added some years back)

 

Present average ages of family =

Sum of present ages of 4 members + Child’s present ages _________________________________________________

5

The average remains the same as it was 4 years back

 

-> 19 = (92 + K) / 5

-> K = 3 years = This is the present ages of the child

Video solution:

Video solution:

Total present age of the friend group = (4x36) = 144 years

Total age of the friend 6 years ago = (144-6x4) = 120 years

At that time, the number of member = 3

Therefore Average age at that time = \frac{120}{3} = 40 years

Video solution:

Let the present ages of Amit and Dhiraj be 5x years and 4x years respectively. Then,
5x + 6 = 26
5x = 20
x = 4
Dhiraj’s age = 4x = 16 years

Video solution:

Explanation:
Let the ages of husband and wife at the time of their 20th wedding anniversary be X years and Y years respectively and X > Y.
Their combined age = (X + Y) years.
The ages of both husband and wife at the time of wedding will be (X – 20) years and (Y – 20) years respectively.
Their combined age = (X – 20) + (Y – 20)
= (X + Y – 40) Years
By first information, we have
(X + Y) = 2( X + Y – 40)
X + Y = 2X + 2Y - 80
Therefore, X + Y = 80-------A
and by second information, we have
X – Y =3 ----------------------B
Solving A and B, we get X = 41.5 years
Therefore, the age of husband at the time of their 20th wedding anniversary X = 41.5 years
Age at the time of marriage = 41.5 years – 20 years = 21.5 years.

Video solution:

Let Neha's present age be 'x' years.
Her age 12 years ago = (x – 12) years
Therefore, her mother's age 12 years ago = 4(x – 12)
Her mother's present age = 4x – 48 + 12 = 4x – 36
Neha's age after 12 years = x + 12
Her mother's age after 12 years = 4x – 36 + 12 = 4x – 24
4x – 24 = 2(x + 12)
4x – 2x = 24 + 24
x = 24
Therefore, Neha's present age = 24
Her mother's present age = 4x – 36 = 4(24) – 36 = 60 years

Video solution: