# 3 Palindromes – TCS Codevita 2020 Problem

3 palindromes Problem is one of the problem that was asked in previous year TCS Codevita Exam. In this problem you have given an input string word and you need to split the string into exactly 3 palindromic substring. This is how to solve the TCS Codevita problem 3 Palindromes in an optimised way. ## Problem Description

In this 3 Palindrome, Given an input string word, split the string into exactly 3 palindromic substrings. Working from left to right, choose the smallest split for the first substring that still allows the remaining word to be split into 2 palindromes. Similarly, choose the smallest second palindromic substring that leaves a third palindromic substring.

If there is no way to split the word into exactly three palindromic substrings, print “Impossible” (without quotes). Every character of the string needs to be consumed.

Cases not allowed –

• After finding 3 palindromes using above instructions, if any character of the original string remains unconsumed.
• No character may be shared in forming 3 palindromes.

Constraints

• 1 <= the length of input sting <= 1000

Input

• First line contains the input string consisting of characters between [a-z].

Output

• Print 3 substrings one on each line.

Time Limit

1

Examples

Example 1

Input

nayannamantenet

Output

nayan

naman

tenet

Explanation

• The original string can be split into 3 palindromes as mentioned in the output.
• However, if the input was nayanamantenet, then the answer would be “Impossible”.

Example 2

Input

aaaaa

Output

a

a

aaa

Explanation

• The other ways to split the given string into 3 palindromes are as follows –
• [a, aaa, a], [aaa, a, a], [aa, aa, a], etc.
• Since we want to minimize the length of the first palindromic substring using left to right processing, the correct way to split is [a, a, aaa].

Example 3

Input

aaaabaaaa

Output

a

aaabaaa

a

Explanation

• The other ways to split the given string into 3 palindromes are as follows –
• [aaaa, b, aaaa], [aa, aabaa, aa], etc.
• Since we want to minimize the length of the first palindromic substring using left to right processing, the correct way to split is [a, aaabaaa, a].

## Solution for 3 Palindromes Problem

`#include<bits/stdc++.h>typedef long long int lld;#define mod 1000000007using namespace std;bool pali(string s){    if(s.length()==1) return true;    string s1=s;reverse(s1.begin(),s1.end());    return (s1==s);}int main(){    speed;    string s,s1,s2,s3;    cin>>s;    int l=s.length();    for(int i=1;i<l-1;i++)    {        s1=s.substr(0,i);        if(pali(s1))            for(int j=1;j<l-i;j++)        {            s2=s.substr(i,j);s3=s.substr(i+j,l-i-j);            if(pali(s2)&&pali(s3))            {                cout<<s1<<endl<<s2<<endl<<s3;return 0;            }        }    }    cout<<"Impossible";    return 0;}`
`import sysdef if_palindrome(s):    if len(s)==1:        return True    s1=s[::-1]    return s1==ss=input()l=len(s)for i in range(1,l-1):    s1=s[:i]    if if_palindrome(s1):        for j in range(1,l-i):            s2=s[i:i+j]            s3=s[i+j:]            if if_palindrome(s2) and if_palindrome(s3):                print(s1)                print(s2)                print(s3)                sys.exit()print("Impossible")`