Once you attempt the question then PrepInsta explanation will be displayed.

E V E R

9 I N C E

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1 0 R W I N

- Clearly, D = 1

- Clearly S = 9

- As one carry must have been from previous step

- A = 0

2. Then we looks at E and I which results in R, as

9 is already occupied by S so E could be 8 and I

could be 7 and R will be 5 with carry 1.

3. Then we place the values of R=5 and E=8

resulting in N=3 with carry 1.

4. In ten’s digits – E=8 and and value of C could

be 3,4,6 (As all others are occupied) and To

make I=7 (previously assigned in step 2) E must

be added by 9 which is already occupied by S.

So this hit ends here.

Now start again with reduced value of E or I,

repeat above steps until you get a correct

answer or a dead end.

5. Repeating above steps one time comes with

E=5 and I=7 which results in R=3 carry=1.

6. Placing R=3 and E=5 in unit digits and their

sum gives 8.

7. in ten’s digits place E=5 now you can add 2 to

make I=7 hence C=2.

8. in 100’s digits you have N=8 (from step 6)

and only digits that are left now are 4 and

6 hence. So placing V=4 you will get W=2 which

is not true because it is already assigned to C.

So we are left with only V=6 as the ultimate

choice and this leads the result in to W=4.

Hence this way we got the answer

Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23

5 6 5 3

9 7 8 2 5

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1 0 3 4 7 8

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