Infosys Quantitative Aptitude Questions and Answers

Infosys Aptitude Questions and Answers can be found here on the Infosys Question Aptitude dashboard. Here the Most Repeated Placement Papers for Infosys Aptitude Round are available. We have updated the Infosys Aptitude Syllabus with the latest Pattern and Information that will help you crack the Infosys Aptitude Test Round. PrepInsta also provides you Infosys Aptitude Questions pdf.

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Aptitude Test for Infosys
Number of Sections 3
Total Marks 65
Type of Exam Non - Adaptive
Mode Conducted Online/Written

Infosys Aptitude Questions Pdf

Topics

13

Time

25 min

Adaptive/Non Adaptive

No

Negative Marking

No

Curriculum

Infosys Aptitude Questions

Click here to know Infosys Aptitude Curriculum

Infosys Syllabus

Infosys Aptitude curriculum 2020

Infosys recent aptitude curriculum is given below:-

More info about Infosys Aptitude Test sections

  • Number of Questions – 10
  • Time Limit – 25 mins
  • Difficulty - Easy-Medium

Infosys Aptitude Paid Materials & online classes

Infosys Previous year Aptitude Questions Answers

infosys-recent-placement-paper-with-solution

Infosys recent aptitude curriculum is given below:-

Question #1

Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of Rs. 300 with an annual increment of Rs. 30. Y asked for an initial salary of Rs. 200 with a rise of Rs. 15 every six months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?

A

Rs. 93,300

Rs. 93,300

29.67%
B

Rs. 93,200

Rs. 93,200

32.42%
C

Rs. 93,100

Rs. 93,100

23.08%
D

None of these

None of these

14.84%
  • PrepInsta Explanation

Question #2

Directions for questions 1 & 2: Answer the questions based on the following information:

A cow is tethered at point A by a rope. Neither the rope nor the cow is allowed to enter the triangle ABC Angle BAC = 30· Also AB =AC =10m.
CAT Mensuration Questions and Answers

Question 1: What is the area that can be grazed by the cow if the length of the rope is 8 m?

A

134π1/3 sq m

134π1/3 sq m

29.13%
B

121π sq m

121π sq m

29.13%
C

132π sq m

132π sq m

25.98%
D

176 π/3 sq m

176 π/3 sq m

15.75%
  • PrepInsta Explanation

Answer : (d)

CAT Mensuration Questions and Answers

The figure shows the prohibited area for the cow and the area the cow can graze. The length of the rope is 8 m whereas the length of the sides id 10 m. Hence the scenario is as explained in the figure above. The height of this triangle can be calculated and is approx 9.6m. So clearly greater than 8 m. So the area grazed by the cow = Area of the circle – Area of the sector of 30o

CAT Mensuration Questions and Answers

 

Question #3

What is the area that can be grazed by the cow if the length of the rope is 12 m?

A

133π1/6 sq m

133π1/6 sq m

15.79%
B

121π sq m

121π sq m

11.58%
C

132π sq m

132π sq m

48.42%
D

176π/3 sq m

176π/3 sq m

24.21%
  • PrepInsta Explanation

Answer: (c)

CAT Mensuration Questions and Answers

Here the length of the rope is 12 m which is greater than the side of the triangle. Neither the cow nor the rope can enter the triangle. The area that can be grazed thereby is the area of the circle – the area of the sector of 30 degrees of the same circle which is equal to

CAT Mensuration Questions and Answers

Question #4

A merchant buys 80 articles, each at Rs. 40. He sells n of them at a profit of n% and the remaining at a profit of (100 – n)%. What is the minimum profit the merchant could have made on this trade?

A

Rs. 2160

Rs. 2160

22.73%
B

Rs. 1420

Rs. 1420

27.27%
C

Rs. 1580

Rs. 1580

42.05%
D

Rs. 2210

Rs. 2210

7.95%
  • PrepInsta Explanation

CP = 80 × 40
Profit from the n objects = n% × 40 × n.
Profit from the remaining objects = (100 – n)% × 40 × (80 – n).
We need to find the minimum possible value of n% × 40 × n + (100 – n)% × 40 × (80 – n).
Or, we need to find the minimum possible value of n2 + (100 – n) (80 – n).
Minimum of n2 + n2 – 180n + 8000
Minimum of n2 – 90n + 4000
Minimum of n2 – 90n + 2025 – 2025 + 4000
We add and subtract 2025 to this expression in order to create an expression that can be expressed as a perfect square.
This approach is termed as the “Completion of Squares” approach. We keep revisiting this in multiple chapters.
Minimum of n2 – 90n + 2025 + 1975 = (n – 45)2 + 1975
This reaches minimum when n = 45.
When n = 45, the minimum profit made
45% × 40 × 45 + 55% × 40 × 35
18 × 45 + 22 × 35 = 810 + 770 = 1580

Question #5

Ramesh plans to order a birthday gift for his friend from an online retailer. However, the birthday coincides with the festival season during which there is a huge demand for buying online goods and hence deliveries are often delayed. He estimates that the probability of receiving the gift, in time, from the retailers A, B, C and D would be 0.6, 0.8, 0.9 and 0.5 respectively. Playing safe, he orders from all four retailers simultaneously. What would be the probability that his friend would receive the gift in time?

A

0.004

0.004

12.2%
B

0.006

0.006

9.76%
C

0.216

0.216

37.8%
D

0.994

0.994

18.29%
E

0.996

0.996

21.95%
  • PrepInsta Explanation

Key Data

  1. Probability that retailer A will deliver the gift P(A) = 0.6
  2. Probability that retailer B will deliver the gift P(B) = 0.8
  3. Probability that retailer C will deliver the gift P(C) = 0.9
  4. Probability that retailer D will deliver the gift P(D) = 0.5

His friend will receive the gift if at least one of the retailers delivers the gift.
Conversely, his friend will not receive the gift only if all four retailers fail to deliver the gift.

So, probability of receiving the gift = 1 – {probability of none of the retailers delivering the gift}

Probability that none of the retailers deliver

The probability of not receiving the gift from retailer A, P(A’) = 1 - P(A) = 1 - 0.6 = 0.4.
The probability of not receiving the gift from retailer B, P(B’) = 1 – 0.8 = 0.2
The probability of not receiving the gift from retailer C, P(C’) = 1 – 0.9 = 0.1
The probability of not receiving the gift from retailer D, P(D’) = 1 – 0.5 = 0.5

The probability that none of the retailers deliver the gift
= P(A’) * P(B’) * P(C’) * P(D’)
= (0.4 × 0.2 × 0.1 × 0.5)
=0.004

Therefore, the probability of Ramesh’s friend receiving a gift
= {1 - 0.004} = 0.996

Question #6

How many pairs of positive integers x, y exist such that HCF (x, y) + LCM (x, y) = 91?

A

10

10

12.94%
B

8

8

48.24%
C

6

6

29.41%
D

7

7

9.41%
  • PrepInsta Explanation

Let us x = h * a; y = h * b
a and b are co-prime. So, LCM of (x, y) = h * a * b

So, in essence h + h * a * b = 91. Or h(ab + 1) = 91
Now, 91 can be written as 1 * 91 or 7 * 13
Or, we can have HCF as 1, LCM as 90 -
There are 4 pairs of numbers like this (2, 45), (9, 10), (1, 90) and (5, 18)

We can have HCF as 7, ab + 1 = 13 => ab = 12 => 1 * 12 or 4 * 3

Or, the pairs of numbers are (7, 84) or (21, 28)

The third option is when HCF = 13, ab + 1 = 7 => ab = 6
Or (a, b) can be either (1, 6) or (2, 3)
The pairs possible are (13, 78) and (26, 39)
There are totally 8 options possible - (2, 45), (9, 10), (1, 90), (5, 18), (7, 84), (21, 28), (13, 78) and (26, 39).
8 Pairs.

Question #7

Kumar started from Chennai at x hrs y minutes and travelled to Vellore. He reached Vellore at y hrs z minutes. If the total travel time was z hrs and x minutes, his starting time in Chennai could have been ______ (Assume clock format to be 0 to 24 hrs).

A

02:08 hrs

02:08 hrs

19.72%
B

13:03 hrs

13:03 hrs

28.17%
C

00:02 hrs

00:02 hrs

36.62%
D

12:01 hrs

12:01 hrs

15.49%
  • PrepInsta Explanation

x, y or z cannot be greater than 24
Also x + y + z cannot be greater than 24
Given x hrs + z hrs = y hrs
Also y min + x min = z min
The only value of x that will satisfy the above 2 equations is 0.
Hence, from among the choices given, the time could be 00:02 hrs

Question #8

Amar, Akbar and Antony decide to have a 'x' m race. Antony completes the race 14 m ahead of Amar. Akbar finishes 20 m ahead of Antony and 32 m ahead of Amar. What is Amar’s speed?

A

9/10th of Antony's speed

9/10th of Antony's speed

32.84%
B

5/8th of Akbar's speed

5/8th of Akbar's speed

26.87%
C

14/15th of Antony's speed

14/15th of Antony's speed

26.87%
D

10/7th of Akbar's speed

10/7th of Akbar's speed

13.43%
  • PrepInsta Explanation

When Antony completes, Amar would have run (x – 14) m; Time taken is the same
Ratio of Amar’s speed : Antony’s speed = x−14/t1 : x/t1 or x−14/x

---- (1)

When Akbar finishes, Amar would have run (x – 32) m; Antony would have run (x – 20) m; Time taken is the same

At this point, the ratio of Amar’s speed : Antony’s speed = x−32/t2: x−20/t2 or x−32/x−20 ---- (2)
Equating (1) and (2), we get
x−14/x = x−32/x−20
x2 – 34x + 280 = x2 – 32x
2x = 280
Or x = 140 m
Ratio of Amar’s speed : Antony’s speed = (140−14)/140 = 126/140 = 9/10

Question #9

Ramesh takes 6.5 hours to go from city A to city B at 3 different speeds 30 kmph, 45 kmph, and 60 kmph covering the same distance with each speed. The respective mileages per liter of fuel are 11 km, 14 km and 18 km for the above speeds. Ramesh's friend Arun is an efficient driver and wants to minimise his friend's car's fuel consumption. So he decides to drive Ramesh's car one day from city A to city B. How much fuel will he be able to save?

A

4.2 liters

4.2 liters

20.31%
B

4.5 liters

4.5 liters

46.88%
C

0.7 liters

0.7 liters

23.44%
D

0.3 liters

0.3 liters

9.38%
  • PrepInsta Explanation

Total time = 6.5 hrs
Let the total distance be x
Ramesh\'s speeds = 30, 45, 60 kmph

6.5 = x/330

+ x/345 + x/360
6.5 = 2x+4x/3+x180
6.5 = 6x+4x+3x540

or x = 270 km

With each speed distance covered = 270/3 = 90 km
Fuel consumed when driving at 30 = 90/11 = 8.1 l
Fuel consumed when driving at 45 = 90/14 = 6.4 l
Fuel consumed when driving at 60 = 90/18 = 5
Total fuel = 8.1 + 6.4 + 5 = 19.5 liters

When Arun drives the car, he should drive at 60 kmph throughout so that he gets the maximum mileage!
Fuel consumption when driving at 60 for entire journey = 270/18 = 15 liters

Question #10

A person invests Rs. 1000 at 10% annual compound interest for 2 years. At the end of two years the whole amount is invested at an annual simple interest of 12% for 5 years. The total value of the investment finally is:

A

1776

1776

18.18%
B

1760

1760

31.82%
C

1920

1920

25.76%
D

1936

1936

24.24%
  • PrepInsta Explanation

Compound interest for 1st 2 years and simple interest for next 5 years.
Interest after 1 year= Rs 100 (10% of 1000)
Thus, prime amount after 1 year=RS 1100
Interest after 2 year= Rs 110 (10% of 1100)
Thus, prime amount=Rs 1210
Interest after 5 years @12% simple interest on Rs 1210
=1210×0.12×5=Rs 726
Hence total value =1210+726= RS 1936

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Student Interview experience

  • Name: Rasool Pookutty
  • Branch: Mechanical
  • College: Jeppiaar Engineering College
  • Type of Interview: On-Campus

Student Interview

Like every year, this year also Infosys invited applications from the contenders who were capable and hardworking of filling up the vacant positions. The company had a strict recruitment process.Eligibility Criteria was 65% in 10th,12th and B.tech.

The Interview Process has three rounds:-

  • Written Round
  • Technical Round
  • HR Round

1st Level

My written round was further divided into Quantitative Aptitude, Logical Reasoning and Verbal English. Each section was allotted with the particular time frame and came with a defined set of questions.

  1. Quantitative Aptitude – Number of Questions (10), Time Limit (25 mins)
  2. Logical Reasoning – Number of Questions (15), Time Limit (35 mins)
  3. Verbal English – Number of Questions (40), Time Limit (35 mins)
  • The time allocated for this online test was 1 hour, 35 minutes
  • There are no negative marks
  • And there was sectional cut off

The average time duration and number of questions for this round are detailed below:

Section Duration No. of Questions
Aptitude:

  • Data Interpretation
  • Permutation and Combination
  • Time and work
  • Profit and Loss
  • Probability
 25 mins 10
English

  • Sentence correction
  • Para Jumbles
  • Reading Comprehensions
  • Analogy
  • Fill in the blanks
 35 mins 40
Logical

  • coding-decoding
  • number series
  • arrangements
  • syllogisms
  • cryptarithmetic
 35 mins. 15

Before appearing for the written round, I practised a few previous years’ papers that I found on PrepInsta. It proved very helpful for me to clear the round and get a concrete idea about the expected questions.Now, the last and final level of the Interview was conducted the next day.

2nd Level

The interviewer of the next round was friendly and moderate for the first few minutes. Later, he shifted all together with the series of questions coming my way. He started with,

  • Explain your project,
  • Tell me two differences between array and pointer.

Well, answering the questions correctly required basic subject knowledge and good confidence to place on the table. This round went a little more moderate when the interview came up with some fundamental question for the round. The few and significant questions that I remember are:

  • What are your strengths and weaknesses?
  • Where do you see yourself in next five years?
  • Why should Infosys hire you?

With all these questions, the interviewer was checking my behavioral and communication skills. I believe Iwas rated on the rating scale to make the final selection. After taking a deep breath upon interview completion, I was eagerly waiting for the final result announcements. But, the wait was worth it. I finally got selected the job on the date of result declaration which was after seven days from my date of interview.

Infosys Aptitude Topics Analytics 2020

Percentages

No Of Questions: 0 - 1
Time - 30sec - 1min
Diffculty Level - Medium
Importance - High

Data Interpretation

No Of Questions: 0 - 1
Time - 1min
Difficulty Level - Moderate
Importance - Easy - Medium

Permutation and Combination

No Of Questions: 1
Time - 30sec - 55sec
Diffculty Level - Easy
Importance - High

Probability

No Of Questions: 0 - 1
Time - 40sec - 55sec
Difficulty Level - Easy -Medium
Importance - Low - Medium

Areas, Shapes, Perimeter

No Of Questions: 0 - 1
Time - 40sec - 55sec
Diffculty Level - Moderate
Importance - Easy

Speed Time and Distance / Boats and Streams

No Of Questions: 1
Time - 40sec
Difficulty Level - Easy
Importance - High

Problem on Ages

No Of Questions: 0 - 1
Time - 30sec - 1min
Difficulty Level - Easy-Medium
Importance - Moderate

Time and Work

No Of Questions: 1
Time - 45sec - 1min
Difficulty Level - Medium
Importance - High

Profit and Loss | Mixtures and Allegation

No Of Questions: 1
Time - 30sec - 45sec - 1min
Difficulty Level -Easy
Importance - Low

Divisibility

No Of Questions: 1 - 2
Time - 35sec -
Difficulty Level - Medium
Importance - High

Number Decimal & Fractions

No Of Questions: 0 - 1
Time - 30sec - 1min
Diffculty Level - Medium
Importance - High

Overall Analytics

Infosys Difficulty level

Total Number of Questions: 10
Time:-25
Suggested time to solve per question:- 50 secs - 1 min 30sec
Importance:- Medium
Difficulty Level:- Moderate

Quants

Cut Off

Diffculty

Importance

Infosys Aptitude Question Papers with Latest Solutions 2020

This table will tell you about Infosys Aptitude questions difficulty and the Minimum time you should take to solve these particular Questions.
INFOSYS APTITUDE TOPICS NO. OF QUESTIONS IN TEST TIME DIFFICULTY
Percentages 0 or 1 2 mins Medium
Data Interpretation 0 or 1 1 min 15 secs Medium
Permutation and Combination     1 1 min 10 secs High
Probability 0 or 1 1 min 25 secs Medium
Areas, Shapes, Perimeter 0 or 1 1 min 30 secs High
Speed Time and Distance / Boats and Streams      1 1 min 25 secs Medium
Problem on Ages 0 or 1 1 min Medium
Time and Work      1 1 min 15 secs High
Profit and Loss | Mixtures and Allegation      1 1 min 15 secs High
Divisibility 1 or 2 1 min 15 secs High
Number Decimal & Fractions 0 or 1 1 min 15 secs High

Infosys Aptitude Papers with Answers Based FAQ’s

Ques. How much time is needed to clear the cut off for infosys quantitative aptitude questions?

Ans. In reference to infosys quantitative aptitude test questions we understand that you just only want to study the Infosys Aptitude Question or Quants section. If you had been preparing general Quants earlier then 3 days are enough. If you haven’t started with any preparation that around 1 week is necessary. Note the Infosys aptitude  exam is very competitive thus you must prepare well.

Ques. Can also prepare from some aptitude books for infosys aptitude Test preparation?

Ans. Yes, we do recommend also studying from some aptitude book for infosys aptitude Questions and Answers and Solve infosys previous year aptitude questions for more practice.

Reviews

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Nishu Sengupta

Infosys

Thankyou prepInsta for making a great website. This website helped me in getting placed. I was worried about aptitude section but my friend suggested me prepinsta for Preparation.And really it helped me alot at the time of infosys aptitude paper.

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